The beam shown in Figure Q.2 consists of a W610 x 140 structural steel wide-flange shape [E = 200 GPa; /= 1120 x 106 mm4]. If w=65 kN/m and P= 124 kN, determine: A 4.3, V 1.5 m B W 3.5 m P UB = 2.5 m D X Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form numerator EI Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

The beam shown in Figure Q.2 consists of a W610 x 140 structural steel wide-flange shape [E = 200 GPa; /= 1120 x 106 mm4]. If w=65 kN/m and P= 124 kN, determine: A 4.3, V 1.5 m B W 3.5 m P UB = 2.5 m D X Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form numerator EI Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter4: Shear Forces And Bending Moments

Section: Chapter Questions

Problem 4.3.22P: Find expressions for shear force V and moment M at v = L/2 of beam AB in structure (a). Express V...

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The beam shown in Figure Q.2 consists of a W610 x 140 structural steel wide-flange shape [E = 200 GPa; /= 1120 x 106 mm4]. If w=65 kN/m and P= 124 kN,
determine:
A
AV, V
1.5 m
B
W
3.5 m
P
2.5 m
D
Figure Q.2
Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D.
a) Calculate the value of the deflection at point B due to uniformly distributed load win the form
UB =
numerator
EI
Note: E/will cancel out in further calculations.
Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

b) Calculate the value of the deflection at point B due to concentrated load P in the form
numerator
EI
UB =
Note: E/will cancel out in further calculations.
Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

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