The beam is carrying a distributed load on segment AB and a concentrated load at point E. Take 4w₁ = 2w2 = 8 kip/ft. a) Determine the support reactions at points A and C. b) Calculate the internal resultant loadings (normal and shear forces and bending moment) at point D and at the midpoint of segment BE. W₂ -6 ft- D hinge 6 ft W₁ B 4 ft 5 kip + Figure 2.1 - Compound beam E 4 ft

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Please help me with this I dont even know how they are defining the load force what does 4w1=2w2=8kip/ft like what does that mean are they all equal to 8kip/ft or the 2w2 is equal to that why not just lable in the figure omg.

The compound beam shown in Figure 2.1 has an internal hinge at point B. It is fixed (clamped) at
point C and supported by a roller at point A. The length of each segment is shown in the figure.
The beam is carrying a distributed load on segment AB and a concentrated load at point E. Take
4w₁ 2w2 = 8 kip/ft.
-
=
a) Determine the support reactions at points A and C.
b) Calculate the internal resultant loadings (normal and shear forces and bending moment) at
point D and at the midpoint of segment BE.
W2
A
-6 ft-
D
hinge
6 ft
W₁
B
-4 ft-
5 kip
Figure 2.1 - Compound beam
E
4 ft
Transcribed Image Text:The compound beam shown in Figure 2.1 has an internal hinge at point B. It is fixed (clamped) at point C and supported by a roller at point A. The length of each segment is shown in the figure. The beam is carrying a distributed load on segment AB and a concentrated load at point E. Take 4w₁ 2w2 = 8 kip/ft. - = a) Determine the support reactions at points A and C. b) Calculate the internal resultant loadings (normal and shear forces and bending moment) at point D and at the midpoint of segment BE. W2 A -6 ft- D hinge 6 ft W₁ B -4 ft- 5 kip Figure 2.1 - Compound beam E 4 ft
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