The beam in Figure 1 has a symmetric cross-section with E = 200 GPa and 1= 17.5×10° mm*: • derive the algebraic expression for the deflection as a function of x = the distance from the left support (A). Use this to calculate the slope at the right end, and the maximum deflection in the beam and its location. 20 kN/m 75kN.m v(x) = j z j dv/dx at right end = Vmax Figure 1 location (i.e. x value) of Vmax =
The beam in Figure 1 has a symmetric cross-section with E = 200 GPa and 1= 17.5×10° mm*: • derive the algebraic expression for the deflection as a function of x = the distance from the left support (A). Use this to calculate the slope at the right end, and the maximum deflection in the beam and its location. 20 kN/m 75kN.m v(x) = j z j dv/dx at right end = Vmax Figure 1 location (i.e. x value) of Vmax =
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![The beam in Figure 1 has a symmetric cross-section with E = 200 GPa and 1= 17.5×10° mm*:
•
derive the algebraic expression for the deflection as a function of x = the distance from the left
support (A).
Use this to calculate the slope at the right end, and the maximum deflection in the beam and its
location.
20 kN/m
75kN.m
v(x) =
j z j
dv/dx at right end
=
Vmax
Figure 1
location (i.e. x value) of Vmax
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a28d6b1-9cd9-4972-b83b-efd9003d1d58%2Fdfc0a1dc-4be2-4e22-aba9-be200111e83f%2F9cglqr6_processed.png&w=3840&q=75)
Transcribed Image Text:The beam in Figure 1 has a symmetric cross-section with E = 200 GPa and 1= 17.5×10° mm*:
•
derive the algebraic expression for the deflection as a function of x = the distance from the left
support (A).
Use this to calculate the slope at the right end, and the maximum deflection in the beam and its
location.
20 kN/m
75kN.m
v(x) =
j z j
dv/dx at right end
=
Vmax
Figure 1
location (i.e. x value) of Vmax
=
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