The beach ball’s volume will increase when Molly goes to the beach. Charles Law can be used to verify this because the pressure inside the beach ball is constant. V1=8.0 L, T1=19 °C, T2= 33 °C. For our Celsius numbers, we must convert them to Kelvin. The temperature can be converted from Celsius to Kelvin just by adding the number 273 to it. T1= (19 °C+273) K, T1= 292 K. T2= (33 °C+273) =, T2=306 K. According to Charles Law, V1/T1=V2/T2. Therefore, 8.0 L/292 K=V2/306 K, V2*292 K=8.0 L*306 K. V2-292 K/292 K=2448 L/292 K. The 292 K cancels out. So, V2= ? L. Since, the volume of the beach ball has increased from 8.0 L to 8.4 L it is fair to say that the beach ball has expanded. When the temperature of the object containing gas increases, it has to expand so the pressure is kept constant. The gas law used to solve this problem is Charles’s Law which states that the volume of a gas is directly proportional to its absolute temperature of the gas when pressure is kept constant. By applying this gas law, I was able to determine how the beach ball would be affected by the change in temperature while keeping the pressure constant.   the final answer for this problem must have one significant figure so round the final answer

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The beach ball’s volume will increase when Molly goes to the beach. Charles Law can be used to verify this because the pressure inside the beach ball is constant. V1=8.0 L, T1=19 °C, T2= 33 °C. For our Celsius numbers, we must convert them to Kelvin. The temperature can be converted from Celsius to Kelvin just by adding the number 273 to it. T1= (19 °C+273) K, T1= 292 K. T2= (33 °C+273) =, T2=306 K. According to Charles Law, V1/T1=V2/T2. Therefore, 8.0 L/292 K=V2/306 K, V2*292 K=8.0 L*306 K. V2-292 K/292 K=2448 L/292 K. The 292 K cancels out. So, V2= ? L. Since, the volume of the beach ball has increased from 8.0 L to 8.4 L it is fair to say that the beach ball has expanded. When the temperature of the object containing gas increases, it has to expand so the pressure is kept constant. The gas law used to solve this problem is Charles’s Law which states that the volume of a gas is directly proportional to its absolute temperature of the gas when pressure is kept constant. By applying this gas law, I was able to determine how the beach ball would be affected by the change in temperature while keeping the pressure constant.

 

the final answer for this problem must have one significant figure so round the final answer based on the significant figure rule.

» Significant Figure Rules
01 >>
All manzere digits are significant.
Zeres that appear between other
HOMZETA digits are always significant.
Zeros that appear in front of all of the
nonzero daits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
à decimal point are not significant.
Right-end zeros in a number with a
This is true whether the seres occur
before or after the decimal point.
337 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,310 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.
For multiplication and division problems, the answer should be
rounded to the same number of significant figures as the
measurement with the least number of significant figures.
For addition and subtraction problems, the answer should be
rounded to the same number of decimal places as the
measurement with the least number of decimal places
1
Transcribed Image Text:» Significant Figure Rules 01 >> All manzere digits are significant. Zeres that appear between other HOMZETA digits are always significant. Zeros that appear in front of all of the nonzero daits are called left-end zeros. Left-end zeros are never significant. Zeros that appear after all nonzero digits are called right-end zeros. à decimal point are not significant. Right-end zeros in a number with a This is true whether the seres occur before or after the decimal point. 337 has three significant figures. 1.897 has four significant figures. 39,004 has five significant figures. 5.02 has three significant figures. 0.008 has one significant figure. 0.000416 has three significant figures. 140 has two significant figures. 75,310 has four significant figures. 620.0 has four significant figures. 19.000 has five significant figures. For multiplication and division problems, the answer should be rounded to the same number of significant figures as the measurement with the least number of significant figures. For addition and subtraction problems, the answer should be rounded to the same number of decimal places as the measurement with the least number of decimal places 1
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