The basic principle of ultrasound imaging works by measuring the time of flight required for a sound pulse to travel from the transducer, bounce off a surface, and return back to the transducer again, as shown below: Object Transducer Sound Echo Pulse d Therefore, the distance between the transducer and object causing the echo can be calculated as: d =z ct Where 't' is the time-of-flight of the signal and 'c' is the speed of sound in the tissue through which the sound is traveling. The speed of sound in soft tissue is generally estimated as c = 1540 m/s. Suppose the clock used to track time-of-flight has a resolution of +1.5 µs. What is the approximate distance d if the time was estimated to be t = 13 µs?
The basic principle of ultrasound imaging works by measuring the time of flight required for a sound pulse to travel from the transducer, bounce off a surface, and return back to the transducer again, as shown below: Object Transducer Sound Echo Pulse d Therefore, the distance between the transducer and object causing the echo can be calculated as: d =z ct Where 't' is the time-of-flight of the signal and 'c' is the speed of sound in the tissue through which the sound is traveling. The speed of sound in soft tissue is generally estimated as c = 1540 m/s. Suppose the clock used to track time-of-flight has a resolution of +1.5 µs. What is the approximate distance d if the time was estimated to be t = 13 µs?
Introductory Circuit Analysis (13th Edition)
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Transcribed Image Text:The basic principle of ultrasound imaging works by measuring the time of flight required for a sound
pulse to travel from the transducer, bounce off a surface, and return back to the transducer again, as
shown below:
Object
Transducer
Sound
Echo
Pulse
d
Therefore, the distance between the transducer and object causing the echo can be
calculated as:
1
d =z ct
Where 't' is the time-of-flight of the signal and 'c' is the speed of sound in the tissue through
which the sound is traveling.
The speed of sound in soft tissue is generally estimated asc = 1540 m/s. Suppose the clock
used to track time-of-flight has a resolution of +1.5 us. What is the approximate distance d
if the time was estimated to be t = 13 µs?
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