The base of a three-dimensional figure is bound by the line y = -x + 1 on the interval [-3, 0]. Vertical cross sections that are perpendicular to the base are isosceles triangles with a height equal to 2. Find the volume of the figure using i = seven slices. Y 54-3-2-1 1 2 3 4 5 n ο v= Σ Α (c;)· Δx i=1 7 ο v= Σ Α (c;)· Δx i=1 7 ο v= Σ Α (c;) i=1 7 O V= † Σ Α (c;) · Δ.x i=1
The base of a three-dimensional figure is bound by the line y = -x + 1 on the interval [-3, 0]. Vertical cross sections that are perpendicular to the base are isosceles triangles with a height equal to 2. Find the volume of the figure using i = seven slices. Y 54-3-2-1 1 2 3 4 5 n ο v= Σ Α (c;)· Δx i=1 7 ο v= Σ Α (c;)· Δx i=1 7 ο v= Σ Α (c;) i=1 7 O V= † Σ Α (c;) · Δ.x i=1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The base of a three-dimensional figure is bound by the line y = -x + 1 on the interval [-3, 0]. Vertical cross sections that are
perpendicular to the base are isosceles triangles with a height equal to 2.
Find the volume of the figure using i = seven slices.
4
3
X
543-2-1 1 2 3 4 5
-2+
-3-
η
ο v= Σ Α (c;)· Δx
i=1
7
ο v= Σ Α (c)· Δx
i=1
7
ο v= Σ Α (c)
i=1
7
1
† Σ Α (c) · Δ.x
i=1
4 Α ω ώ ΕΙ
4+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6539f692-5656-46fd-b828-f0fe9bb331a2%2F10471df0-d6f6-4d31-9a58-b7c20bbefac5%2Fnk5lv8j_processed.png&w=3840&q=75)
Transcribed Image Text:The base of a three-dimensional figure is bound by the line y = -x + 1 on the interval [-3, 0]. Vertical cross sections that are
perpendicular to the base are isosceles triangles with a height equal to 2.
Find the volume of the figure using i = seven slices.
4
3
X
543-2-1 1 2 3 4 5
-2+
-3-
η
ο v= Σ Α (c;)· Δx
i=1
7
ο v= Σ Α (c)· Δx
i=1
7
ο v= Σ Α (c)
i=1
7
1
† Σ Α (c) · Δ.x
i=1
4 Α ω ώ ΕΙ
4+
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