The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are right triangles with height equal to 8. Algebraically, what is the area of each triangle? -54 Sp = 4 2 0 A = √√9-y² O A = 8 9 O A= 45 /9 + O A = 2₁/9

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are
right triangles with height equal to 8.
Algebraically, what is the area of each triangle?
543
45
0 A = √√9-y²
0 A = 8√√9-y²
O A = 4√√9+ y²
0 A = 2√√9-y²
Transcribed Image Text:The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are right triangles with height equal to 8. Algebraically, what is the area of each triangle? 543 45 0 A = √√9-y² 0 A = 8√√9-y² O A = 4√√9+ y² 0 A = 2√√9-y²
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