Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
The barometric pressure in the center of a cyclone is 29.2 inches of Hg. What is the pressure in kPa?
**Answer Box:**
[______] kPa
---
**Detailed Explanation:**
This problem requires converting the barometric pressure from inches of mercury (inHg) to kilopascals (kPa).
**Conversion Factor:**
1 inch of Hg = 3.38639 kPa
**Steps:**
1. **Identify the given barometric pressure**: 29.2 inches of Hg.
2. **Use the conversion factor**: Multiply the pressure in inches of Hg by the conversion factor to get the pressure in kPa:
\[
29.2 \, \text{inHg} \times 3.38639 \, \text{kPa/inHg} = \text{Pressure in kPa}
\]
3. **Calculate the result** to find the pressure in kPa and input your answer in the provided box.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5708a06e-b85b-454e-b228-7fe5c248a23c%2Fa6b36759-af80-4308-97ab-3c8e2b1e2030%2Fwads5xd_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
The barometric pressure in the center of a cyclone is 29.2 inches of Hg. What is the pressure in kPa?
**Answer Box:**
[______] kPa
---
**Detailed Explanation:**
This problem requires converting the barometric pressure from inches of mercury (inHg) to kilopascals (kPa).
**Conversion Factor:**
1 inch of Hg = 3.38639 kPa
**Steps:**
1. **Identify the given barometric pressure**: 29.2 inches of Hg.
2. **Use the conversion factor**: Multiply the pressure in inches of Hg by the conversion factor to get the pressure in kPa:
\[
29.2 \, \text{inHg} \times 3.38639 \, \text{kPa/inHg} = \text{Pressure in kPa}
\]
3. **Calculate the result** to find the pressure in kPa and input your answer in the provided box.
![An open-end mercury manometer is used to measure the pressure of a confined sample of gas at 15°C, as shown in the figure below.
Atmospheric pressure is 728 torr, the difference in height (h) is 19.1 cm. What is the pressure of the confined gas in atm?
**Diagram Explanation:**
- The diagram illustrates a U-shaped open-end mercury manometer.
- On the left side, there is a bulb connected to the manometer containing gas.
- On the right side, the manometer is open to the atmosphere.
- The height difference (h) between the mercury levels in the two arms of the manometer is labeled, and is given as 19.1 cm.
- The pressure due to the height difference in the mercury column is added to or subtracted from atmospheric pressure to determine the gas pressure.
\[\_\_\_\_\_\_] atm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5708a06e-b85b-454e-b228-7fe5c248a23c%2Fa6b36759-af80-4308-97ab-3c8e2b1e2030%2F5s83zec_processed.png&w=3840&q=75)
Transcribed Image Text:An open-end mercury manometer is used to measure the pressure of a confined sample of gas at 15°C, as shown in the figure below.
Atmospheric pressure is 728 torr, the difference in height (h) is 19.1 cm. What is the pressure of the confined gas in atm?
**Diagram Explanation:**
- The diagram illustrates a U-shaped open-end mercury manometer.
- On the left side, there is a bulb connected to the manometer containing gas.
- On the right side, the manometer is open to the atmosphere.
- The height difference (h) between the mercury levels in the two arms of the manometer is labeled, and is given as 19.1 cm.
- The pressure due to the height difference in the mercury column is added to or subtracted from atmospheric pressure to determine the gas pressure.
\[\_\_\_\_\_\_] atm
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