**Question:**The barometric pressure in the center of a cyclone is 29.2 inches of Hg. What is the pressure in kPa?**Answer Box:**[______] kPa---**Detailed Explanation:**This problem requires converting the barometric pressure from inches of mercury (inHg) to kilopascals (kPa). **Conversion Factor:**1 inch of Hg = 3.38639 kPa**Steps:**1. **Identify the given barometric pressure**: 29.2 inches of Hg.2. **Use the conversion factor**: Multiply the pressure in inches of Hg by the conversion factor to get the pressure in kPa: \[ 29.2 \, \text{inHg} \times 3.38639 \, \text{kPa/inHg} = \text{Pressure in kPa} \]3. **Calculate the result** to find the pressure in kPa and input your answer in the provided box. An open-end mercury manometer is used to measure the pressure of a confined sample of gas at 15°C, as shown in the figure below.Atmospheric pressure is 728 torr, the difference in height (h) is 19.1 cm. What is the pressure of the confined gas in atm?**Diagram Explanation:**- The diagram illustrates a U-shaped open-end mercury manometer.- On the left side, there is a bulb connected to the manometer containing gas.- On the right side, the manometer is open to the atmosphere.- The height difference (h) between the mercury levels in the two arms of the manometer is labeled, and is given as 19.1 cm.- The pressure due to the height difference in the mercury column is added to or subtracted from atmospheric pressure to determine the gas pressure.\[\_\_\_\_\_\_] atm

Hello. Since your question has multiple parts, we will solve the first question for you. If you want the remaining parts to be solved, then please resubmit the whole question and specify those parts you want us to solve.As 1 inches of Hg = 3386 Pa So, 29.2 inches of Hg = (29.2×3386)Pa = 98871.2 Pa As 1 kPa = 1000 Pa So, 98871.2 Pa = (98871.2/1000)kPa = 98.9 kPa (approx.) Hence, pressure = 98.9 kPa

Answered: The barometric pressure in the center…

Science

Chemistry

The barometric pressure in the center of a cyclone is 29.2 inches of Hg. What is the pressure in kPa?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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