The bar shown is subjected to a tensile load of 160KN. If the stress in the middle portion is limited to 150 Newton per millimeter squared, determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is 0.2mm. Young's modulus is given as equal to 2.1x10^5 Newton
The bar shown is subjected to a tensile load of 160KN. If the stress in the middle portion is limited to 150 Newton per millimeter squared, determine the diameter of the middle portion. Find also the length of the middle portion if the total elongation of the bar is 0.2mm. Young's modulus is given as equal to 2.1x10^5 Newton
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:3:10 O
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10
10 cm x 10 cm
Aluminium bar
38 cm
Your answer
The bar shown is subjected to a
tensile load of 160kN. If the stress in
the middle portion is limited to 150
Newton per millimeter squared,
determine the diameter of the middle
portion. Find also the length of the
middle portion if the total elongation
of the bar is O.2mm. Young's modulus
is given as equal to 2.1x10^5 Newton
per millimeter squared.
160 kN
160 KN
6 cm DIA
6 cm DIA
40 cm
Your answer
II
Transcribed Image Text:3:10 O
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A member formed by connecting a
steel bar into an aluminum bar.
Assuming that the bars are prevented
from buckling sideways, calculate the
magnitude of force P that will cause
the total length of the member to
decrease by 0.25mm. The values for
elastic modulus for steel and
aluminum 2.1x10^5 Newton per
millimeter squared and 7x10^4
Newton per millimeter squared
respectively.
5 cm x 5 cm
Šteel bar
30 cm
t0 cm x 10 cm
Aluminium bar
38 cm
Your answer
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