The Balmer series for the hydrogen atom comprises electron energy transitions that end in the n, 2 state. E (eV) 0.00 -0.378 -0.544 2 0.850 4 -1.512 -3.401 Balmer series Consider the four illustrated transitions, each shown by a downward arrow in this energy-level diagram for the hydrogen atom. Because these transitions all involve a hydrogen atom losing energy, they each correspond to the emission of a photon. (a) What is the initial quantum number, n, of the transition that generates the photon with the longest wavelength? (Restrict your attention to the four illustrated transitions.) (b) What is the energy (in eV) of that longest-wavelength photon? ev (c) What is its wavelength (in nm)? nm ENERGY

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The Balmer series for the hydrogen atom comprises electron energy transitions that end in the n,- 2 state.
E (eV)
0.00
-0.378
-0.544 2
-0.850 4
-1.512
-3.401
Balmer
series
Consider the four illustrated transitions, each shown by a downward arrow in this energy-level diagram for the hydrogen atom.
Because these transitions all involve a hydrogen atom losing energy, they each correspond to the emission of a photon.
(a) What is the initial quantum number, n, of the transition that generates the photon with the longest wavelength? (Restrict your
attention to the four illustrated transitions.)
n, -
(b) What is the energy (in ev) of that longest-wavelength photon?
ev
(c) What is its wavelength (in nm)?
nm
Now consider the transition (out of the four depicted) that generates the photon with the shortest wavelength.
(d) What is the initial quantum number, n, of the transition that generates the photon with the shortest wavelength? (Again,
restrict your attention to the four illustrated transitions.)
(e) What is that photon's energy (in ev)?
ev
(f) What is that photon's wavelength (in nm)?
nm
(g) Finally, consider all transitions from n, > 2 that end at n,- 2 (in other words, the entire Balmer sequence, not limited to the
four illustrated transitions). What is the shortest possible wavelength (in nm) for any photon picked from the Balmer series?
nm
ENERGY
6349
Transcribed Image Text:The Balmer series for the hydrogen atom comprises electron energy transitions that end in the n,- 2 state. E (eV) 0.00 -0.378 -0.544 2 -0.850 4 -1.512 -3.401 Balmer series Consider the four illustrated transitions, each shown by a downward arrow in this energy-level diagram for the hydrogen atom. Because these transitions all involve a hydrogen atom losing energy, they each correspond to the emission of a photon. (a) What is the initial quantum number, n, of the transition that generates the photon with the longest wavelength? (Restrict your attention to the four illustrated transitions.) n, - (b) What is the energy (in ev) of that longest-wavelength photon? ev (c) What is its wavelength (in nm)? nm Now consider the transition (out of the four depicted) that generates the photon with the shortest wavelength. (d) What is the initial quantum number, n, of the transition that generates the photon with the shortest wavelength? (Again, restrict your attention to the four illustrated transitions.) (e) What is that photon's energy (in ev)? ev (f) What is that photon's wavelength (in nm)? nm (g) Finally, consider all transitions from n, > 2 that end at n,- 2 (in other words, the entire Balmer sequence, not limited to the four illustrated transitions). What is the shortest possible wavelength (in nm) for any photon picked from the Balmer series? nm ENERGY 6349
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