The balanced equation below shows the reaction which occurs between silver nitrate and sodium chloride. For your convenience, the molar mass of each substance is shown below their formulas (in purple). By clicking options in the word bank below, complete the sentence which follows. Each word bank item is only used once. AgNO3(aq) + NaCl(aq) AgCI(s) + NaNO3(aq) -> 169.875 58.443 143.321 84.997 to be in excess. We Given 8.0 g of silver nitrate and 1.2 g of sodium chloride, we would expect predict that the reaction will produce to be limiting and kg of silver chloride as a precipitate when collected via filtration.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The balanced equation below shows the reaction which occurs between silver nitrate and sodium chloride. For your convenience, the molar
mass of each substance is shown below their formulas (in purple). By clicking options in the word bank below, complete the sentence which
follows. Each word bank item is only used once.
AGNO3(aq) + NaCl(aq) -> AgCI(s) + NaNO3(aq)
169.875
58.443
143.321
84.997
to be limiting and
to be in excess. We
Given 8.0 g of silver nitrate and 1.2 g of sodium chloride, we would expect
predict that the reaction will produce
kg of silver chloride as a precipitate when collected via filtration.
Transcribed Image Text:The balanced equation below shows the reaction which occurs between silver nitrate and sodium chloride. For your convenience, the molar mass of each substance is shown below their formulas (in purple). By clicking options in the word bank below, complete the sentence which follows. Each word bank item is only used once. AGNO3(aq) + NaCl(aq) -> AgCI(s) + NaNO3(aq) 169.875 58.443 143.321 84.997 to be limiting and to be in excess. We Given 8.0 g of silver nitrate and 1.2 g of sodium chloride, we would expect predict that the reaction will produce kg of silver chloride as a precipitate when collected via filtration.
The balanced equation below shows the reaction of iron metal and oxygen gas to form rust, Fe,03. For your convenience, the molar mass of
each substance is shown below their formulas (in purple). By clicking options in the word bank below, complete the sentence which follows.
Each word bank item is only used once.
4 Fe(s) + 3 02(g) -> 2 Fe,03(s)
55.845
32
159.69
Given 0.60 g of iron and 0.85 g of oxygen gas, we would expect
that the reaction will produce
to be limiting and
to be in excess. We predict
mg of rust as a result.
Transcribed Image Text:The balanced equation below shows the reaction of iron metal and oxygen gas to form rust, Fe,03. For your convenience, the molar mass of each substance is shown below their formulas (in purple). By clicking options in the word bank below, complete the sentence which follows. Each word bank item is only used once. 4 Fe(s) + 3 02(g) -> 2 Fe,03(s) 55.845 32 159.69 Given 0.60 g of iron and 0.85 g of oxygen gas, we would expect that the reaction will produce to be limiting and to be in excess. We predict mg of rust as a result.
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