The axial com An aluminum right-circular cylinder surrounds a steel cylinder as shown in Fig. load of 200 kN is applied through the rigid cover plate shown. If the aluminum cylinder is originally 0.25 mm longer than the steel before any load is applied, find the normal stress in each when the temperature has dropped 20 K and the entire load is acting. For steel take E = 200 GPa, a = 12 x 10PC, and for aluminum assume E=70 GPa, a= 25 x 10rC. Ans. o=9 MPa, o = 15.5 MPa

The axial com An aluminum right-circular cylinder surrounds a steel cylinder as shown in Fig. load of 200 kN is applied through the rigid cover plate shown. If the aluminum cylinder is originally 0.25 mm longer than the steel before any load is applied, find the normal stress in each when the temperature has dropped 20 K and the entire load is acting. For steel take E = 200 GPa, a = 12 x 10PC, and for aluminum assume E=70 GPa, a= 25 x 10rC. Ans. o=9 MPa, o = 15.5 MPa

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.10.11P: A pressurized circular cylinder has a sealed cover plate fastened with steel bolts (see figure). The...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

An aluminum right-circular cylinder surrounds a steel cylinder as shown in Fig. 1-29. The axial compressive
load of 200 kN is applied through the rigid cover plate shown. If the aluminum cylinder is originally 0.25 mm
longer than the steel before any load is applied, find the normal stress in each when the temperature has dropped
20 K and the entire load is acting. For steel take E = 200 GPa, a = 12 x 10 C, and for aluminum assume
E= 70 GPa, a= 25 x 10rC.
Ans. o= 9 MPa, o = 15.5 MPa
%3D
200 kN
500 mm
80 mm
85 mm
141 mm
Fig. 1-29

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