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The average sunshine hours per year in a city have a normal distribution with a mean of 1,789 hours and a standard deviation of 94 hours. Use the normal distribution tables to determine the probability that the sunshine hours per ear are: Less than 2,061.6 hours: P(x2,061.6) = = • Between 1,842.58 and 1,865.14 hours: P (1,842.58 < x < 1,865.14) • More than 1,865.14 hours: P (x > 1,865.14) : = Keep 2 decimal points in the calculation of the standard normal variable Z).

The average sunshine hours per year in a city have a normal distribution with a mean of 1,789 hours and a standard deviation of 94 hours. Use the normal distribution tables to determine the probability that the sunshine hours per ear are: Less than 2,061.6 hours: P(x2,061.6) = = • Between 1,842.58 and 1,865.14 hours: P (1,842.58 < x < 1,865.14) • More than 1,865.14 hours: P (x > 1,865.14) : = Keep 2 decimal points in the calculation of the standard normal variable Z).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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The average sunshine hours per year in a city have a normal distribution with a mean of 1,789 hours and a standard deviation of 94 hours. Use the normal distribution tables to determine the probability that the sunshine hours per year are: Less than 2,061.6 hours : P(x2,061.6) = • Between 1,842.58 and 1,865.14 hours: P (1,842.58 < x < 1,865.14) = • More than 1,865.14 hours: P(x > 1,865.14) : = Keep 2 decimal points in the calculation of the standard normal variable (z).
Transcribed Image Text:The average sunshine hours per year in a city have a normal distribution with a mean of 1,789 hours and a standard deviation of 94 hours. Use the normal distribution tables to determine the probability that the sunshine hours per year are: Less than 2,061.6 hours : P(x2,061.6) = • Between 1,842.58 and 1,865.14 hours: P (1,842.58 < x < 1,865.14) = • More than 1,865.14 hours: P(x > 1,865.14) : = Keep 2 decimal points in the calculation of the standard normal variable (z).
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