The average speed vavg is given by the following equation. d + d t + t2 d + d Total distance avg Total time d/ D/P. m/s) + d/( m/s) 2d m/s)d/( |m²/s²)
The average speed vavg is given by the following equation. d + d t + t2 d + d Total distance avg Total time d/ D/P. m/s) + d/( m/s) 2d m/s)d/( |m²/s²)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![The average speed vava is given by the following equation.
Total distance
d + d
avg
tị + t2
d + d
Total time
1.
D/P
m/s) + d/(
m/s)
2d
m/s)d/(
m2/s?)
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9974cb88-485f-4954-981d-1d67477878d4%2F7d9553e6-0ab6-4709-a9ab-02b274c6a0f6%2Fdrj8ul6_processed.png&w=3840&q=75)
Transcribed Image Text:The average speed vava is given by the following equation.
Total distance
d + d
avg
tị + t2
d + d
Total time
1.
D/P
m/s) + d/(
m/s)
2d
m/s)d/(
m2/s?)
||
![(a) The average speed during any time interval is equal to the total distance of travel divided by the total
time. Let d represent the distance between O and ®. Let t, be the time for which she has the higher speed
d
Let t, represent the longer time for the return trip at 3.25 m/s =
t1
-. Then the times are
t2
of 5.25 m/s
= -
(5.25
and
5.25 m/s)
d
t2
(3.25
3.25 m/s)
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9974cb88-485f-4954-981d-1d67477878d4%2F7d9553e6-0ab6-4709-a9ab-02b274c6a0f6%2Fmtlnm9_processed.png&w=3840&q=75)
Transcribed Image Text:(a) The average speed during any time interval is equal to the total distance of travel divided by the total
time. Let d represent the distance between O and ®. Let t, be the time for which she has the higher speed
d
Let t, represent the longer time for the return trip at 3.25 m/s =
t1
-. Then the times are
t2
of 5.25 m/s
= -
(5.25
and
5.25 m/s)
d
t2
(3.25
3.25 m/s)
||
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