The average speed of 64 random cars traveling on a certain highway was 80 km/h and the sample standard deviation was 20 km/h. What is the margin of error with a 98% level of confidence for the population average speed? Select one: а. 1.295 b. 2.387 C. 6.64 d. 3.2375 е. 2.656 f. 5.9675
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- At a large university, data were collected on the number of sisters and brothers that each student had. Let therandom variable X represent the number of sisters and the random variable Y represent the number ofbrothers. The distribution of X has mean 1.00 and standard deviation 0.94. The distribution of Y has mean1.07 and standard deviation 1.04. What is the mean of the distribution of X+Y? WHAT IS THE CORRECT ANSWER A. 1.98 B. 2.01 C. 2.04 D. 2.0528 E. 2.07For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to: А. 11 С. 12 В. 14 D. 13The mean height of American women is 64.5 inches. Suppose we select ten Americans women at random and the mean of the heights of the ten women is 63.1 . The number 64.5 is a.... statistic parameter sample population
- Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 77.3 Mbps. The complete list of 50 data speeds has a mean of x = 18.24 Mbps and a standard deviation of s = 17.77 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? a. The difference is (Type an integer or a Mbps. decimal. Do not round.) b. The difference is (Round to two decimal standard deviations. places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The carrier's highest data speed is CThe reading speed of second grade students in a large city is approximately normal, with mean of 91 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). O B. If 100 different students were chosen from this population, we would expect to read exactly 95 words per minute. O C. If 100 different students were chosen from this population, we would expect to read less than 95 words per minute. (b) What is the probability that a random sample of 13 second grade students from the city results in a mean reading rate of more than 95 words per minute? The probability is 0.0746. (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. O A. If 100 independent samples of n = 13 students were chosen from this population, we would expect sample(s) to have a sample mean reading rate of exactly 95 words per minute. O B. If 100 independent samples of n = 13 students were…Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 71.9 Mbps. The complete list of 50 data speeds has a mean of x 17.38 Mbps and a standard deviation of s = 19.81 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a))? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
- The mean height of 790 students in a school is 151 cm and the standard deviation is 15 cm. Assume that the heights are normally distributed. How many students have heights between 119.5 cm and 155.5 cm? Select one: a. 474 students b. 381 students c. 316 students d. 93 students e. 395 studentsResearchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.6 Mbps. The complete list of 50 data speeds has a mean of x=18.29 Mbps and a standard deviation of s=19.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? Question content area bottom Part 1 a. The difference is 54.3154.31 Mbps. (Type an integer or a decimal. Do not round.) Part 2 b. The difference is enter your response here standard deviations. (Round to two decimal places as needed.)Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.5 Mbps. The complete list of 50 data speeds has a mean of x=18.25 Mbps and a standard deviation of s=17.86 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
- Most people think that the "normal" adult body temperature is 98.6°F. In a more recent study, researchers reported that a more accurate figure may be 98.1°F. Furthermore, the standard deviation appeared to be around 0.7°F. Assume that a Normal model is appropriate. b) What fraction of people would be expected to have body temperatures above 98.6°F?The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.02 level that the medicine relieves pain in more than 346 seconds. For a sample of 58 patients, the mean time in which the medicine relieved pain was 352 seconds. Assume the population standard deviation is 23. Find the P-value of the test statistic. 囲 Tables E Keypad Keyboard Shortcuts 0.0582 %3D IXResearchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 73.7 Mbps. The complete list of 50 data speeds has a mean of x = 16.05 Mbps and a standard deviation of s = 17.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? ..... a. The difference is Mbps. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The carrier's highest data speed is Next MacBook F12 DD F11 DII F10 F9 F8 888 00 F7 F6 F5 F4 F3 F2 F1 & ! @ # $ 7 8 4 5 6…