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The average score of 100 students taking a statistics final was 78 with a standard deviation of 7. Assuming a normal distribution, what is the probability that a student scored greater than 66? Multiple Cholce 0.4564 0.9564 -1.714 0.0436

The average score of 100 students taking a statistics final was 78 with a standard deviation of 7. Assuming a normal distribution, what is the probability that a student scored greater than 66? Multiple Cholce 0.4564 0.9564 -1.714 0.0436

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Question:** The average score of 100 students taking a statistics final was 78, with a standard deviation of 7. Assuming a normal distribution, what is the probability that a student scored greater than 66? **Multiple Choice Options:** - ( ) 0.4564 - ( ) 0.9564 - ( ) -1.714 - ( ) 0.0436 **Explanation of Concepts:** This question involves calculating the probability of a student scoring above a certain value when given a normal distribution. With a mean score of 78 and a standard deviation of 7, you can use the properties of the normal distribution to find the probability. The Z-score can be used here, calculated with the formula: \[ Z = \frac{X - \mu}{\sigma} \] where \( X \) is the score of interest (66 in this case), \( \mu \) is the mean (78), and \( \sigma \) is the standard deviation (7). After finding the Z-score, you can use a Z-table or calculator to find the corresponding probability.
Transcribed Image Text:**Question:** The average score of 100 students taking a statistics final was 78, with a standard deviation of 7. Assuming a normal distribution, what is the probability that a student scored greater than 66? **Multiple Choice Options:** - ( ) 0.4564 - ( ) 0.9564 - ( ) -1.714 - ( ) 0.0436 **Explanation of Concepts:** This question involves calculating the probability of a student scoring above a certain value when given a normal distribution. With a mean score of 78 and a standard deviation of 7, you can use the properties of the normal distribution to find the probability. The Z-score can be used here, calculated with the formula: \[ Z = \frac{X - \mu}{\sigma} \] where \( X \) is the score of interest (66 in this case), \( \mu \) is the mean (78), and \( \sigma \) is the standard deviation (7). After finding the Z-score, you can use a Z-table or calculator to find the corresponding probability.
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