The average salary of 81 random employees in a certain financial sector was 3400 USD. The sample standard deviation was 270 USD. We are interested in the 90% confidence interval for the population mean. What is the value of the ta/2 used? Select one: O a. 1.664 O b. 1.292 O c. 2.374 O d. 2.639 Ое. е. 1.990 O f. 0.846

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Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…

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Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given : Margin of error = 5 α = 0.05 Population standard deviation = σ = 30 zα2 = z0.052 = 1.96

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Q: x¯ = Margin of error at 90% confidence level = 90% confidence interval =

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Q: If the sample mean is 37.7 and population standard deviation is = 9.2 and the sample size is 100…

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