The average running times of disks produced by Company A is 88.1 minutes and a standard deviation of 6.1 minutes, while Company B obtained a mean running times of 99.3 minutes with a standard deviation of 13.6 minutes. Assume the population are approximately normally distributed. Solve the probability when a random sample of 41 disks from Company B has a mean running times that at most 15 minutes more than the mean running times of a random sample of 32 disks from Company A.
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- A major television manufacturer has determined that its 40-inch LED televisions have a mean service life that can be modeled by a normal distribution with a mean of six years and a standard deviation of one-half year. If the manufactuerer offers service contracts of four years on these televisions what percentage can be expected to fail from wear-out during the service period?Suppose the birth weights of babies in a particular country are normally distributed with a mean of 3650g and a standard deviation of 425g. If a hospital plans to set up an automatic diabetes screening program for the heaviest 15% of babies, what is the minimum weight that would be automatically screened?An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-temperature performance. A sample of 60 transistors of type A were tested and were found to have a mean lifetime of 1827 hours and a standard deviation of 174 hours. A sample of 180 transistors of type B were tested and were found to have a mean lifetime of 1658 hours and a standard deviation of 231 hours. Let ux represent the population mean for transistors of type A and µy represent the population mean for transistors of type B. Find a 95% confidence interval for the difference uy – µy . Round the answers to three decimal places. The 95% confidence interval is
- Times for a surgical produce are normally distributed. There are two methods. Method A has a mean of 31 minutes and a standard deviation of 3 minutes while method B has a mean of 35 and a standard deviation of 1.5 minutes. Which procedure is preferred if the procedure must be completed within 30 minutes method A or B? which procedure is preferred if the procedure must be completed within 39.5 minutes method B or either method? which produce is preferred if the procedure must be completed within 39 minutes method B or either method?A soft-drink machine is regulated so that the amount of drink dispensed averages 240 milliliters with a standard deviation of 15 milliliters. Periodically, the machine is checked by taking a sample of 40 drinks and computing the average content. If the mean of the 40 drinks is a value within 2 standard deviations from the mean , the machine is thought to be operating satisfactorily; otherwise, adjustments are made. If the company official found the mean of 40 drinks to be 236 milliliters and concluded that the machine needed no adjustment. Was this a reasonable decision?Aresearcher claims that the stomachs of blue crabs from Location A contain more fish than the stomachs of blue crabs from Location B. The stomach contents of a sample of 14 blue crabs from Location A contain a mean of 194 milligrams of fish and a standard deviation of 39 milligrams. The stomach contents of a sample of 8 blue crabs from Location B contain a mean of 187 milligrams of fish and a standard deviation of 44 milligrams. Al a 0 10, can you support the researcher's claim? Assume the population variances are equal. Complete parts (a) through (d) below. (a) Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: H-220 O B. Ho H-2 0 (b) Find the standardized test statistic for u - t=0.381 (Round to three decimal places as needed) Enter your answer in the answer box and then click Check Answer parts remaining Clear All Check Answer leste ppt_08_03.pptx Open file Show all P Type here to search 235 PM 2/21/2021 ts fho sk hz home end insert delet esc & @…
- Two types of plastic are suitable for use by an electronics component manufacturer. The breaking strength of this plastic is important. It is known that the population standard deviation of breaking strength for the two types of plastic are equal and known to be 1.0 psi. A random sample of 10 type 1 plastic produced a mean breaking strength of 162.7 psi while a random sample of 12 type 2 plastic produced a mean breaking strength of155.4 psi. The company will not adopt plastic type 1 unless its mean breaking strength exceeds that of plastic type 2 by at least 10 psi. Based on the sample data obtained, should the company adopt plastic type 1? Perform a hypothesis test at the 5% level of significance.Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2600 grams and a standard deviation of 800 grams while babies born after a gestation period of 40 weeks have a mean weight of 2800 grams and a standard deviation of 450 grams. If a 34-week gestation period baby weighs 2350 grams and a 40-week gestation period baby weighs 2550 grams find the corresponding z-scores. Which baby weighs less relative to the gestation period? (Choose correct answer round to two decimal places as needed). a) the baby born in week 40 weighs relatively less since it's z-score, ____, is smaller than the z-score of _____ for the baby born in week 34. b) the baby born in week 34 weighs relatively less since its z-score, ______, is larger than the z-score of _____ for the baby born in week 40. c) the baby born in week 34 weighs relatively less since its z-score, _____, is smaller than the z-score of ______ for the baby born in week 40. d) the baby born in week 40 weighs…The weight of crabs is normally distributed with mean 28.5 ounces and standard deviation of 3 ounces. A new breeder claims that he can breed crabs yielding a mean weight of more than 28 ounces. A random sample of 36 crabs from the new breeder had a mean weight of 29.2 ounces. A researcher wants to determine if the breeder's claim is true at a = 5%.
- Suppose there are two different vaccines for Covid, Vaccine X and Vaccine Y. An interesting question is which vaccine has a higher 6-month antibody effectiveness quotient (6AEQ). To examine this we randomly select 78 recipients of vaccine X and 93 recipients on vaccine Y. The vaccine X recipients had a mean 6AEQ of x = 151. The vaccine Y recipients had a mean 6AEQ of y = 148. It is recognized that the true standard deviation of 6AEQ for vaccine X recipients is o, = 9.7 while it is recognized that the true standard deviation of 6AEQ for vaccine Y recipients is o, = 10.5. The true (unknown) mean 6AEQ for vaccine X recipients is ly, while the true (unknown) mean 6AEQ for vaccine Y recipients is y. 6AEQ measurements are known to be a normally distributed. In summary: Sample Size Sample Mean Standard Deviation Туре Vaccine 78 93 151 Vaccine 148 10.5 Calculate the variance of the random variable X which is the mean of the 6AEQ measurements of the 78 vaccine X recipients. Calculate the…Suppose there are two different vaccines for Covid, Vaccine X and Vaccine Y. An interesting question is which vaccine has a higher 6-month antibody effectiveness quotient (6AEQ). To examine this we randomly select 78 recipients of vaccine X and 93 recipients on vaccine Y. The vaccine X recipients had a mean 6AEQ of x = 151. The vaccine Y recipients had a mean 6AEQ of y = 148. It is recognized that the true standard deviation of 6AEQ for vaccine X recipients is o, = 9.7 while it is recognized that the true standard deviation of 6AEQ for vaccine Y recipients is o, = 10.5. The true (unknown) mean SAEQ for vaccine X recipients is ly, while the true (unknown) mean 6AEQ for vaccine Y recipients is 4,. 6AEQ measurements are known to be a normally distributed. summary: Sample Size Sample Mean Standard Deviation 9.7 Гуре Vaccine 78 151 Vaccine Y 93 148 10.5 What is the length of your 96% confidence interval for uy Hy ? ) If we used this data to test Hg: Hy - Hy =0 against the alternative H: uy…Suppose there are two different vaccines for Covid, Vaccine X and Vaccine Y. An interesting question is which vaccine has a higher 6-month antibody effectiveness quotient (6AEQ). To examine this we randomly select 78 recipients of vaccine X and 93 recipients on vaccine Y. The vaccine X recipients had a mean 6AEQ of x = 151. The vaccine Y recipients had a mean 6AEQ of y = 148. It is recognized that the true standard deviation of 6AEQ for vaccine X recipients is 0x = 8.7 while it is recognized that the true standard deviation of 6AEQ for vaccine Y recipients is dy = 11.5. The true (unknown) mean 6AEQ for vaccine X recipients is μx, while the true (unknown) mean 6AEQ for vaccine Y recipients is y. 6AEQ measurements are known to be a normally distributed. In summary: Type Sample Size Sample Mean Standard Deviation Vaccine X 78 Vaccine Y 93 151 148 8.7 11.5 a) Calculate the variance of the random variable X which is the mean of the 6AEQ measurements of the 78 vaccine X recipients.…