Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
The average of five distinct integers is 65. If the largest integer is 75, what is the maximum possible value of the smallest integer? (A) 1 (B) 31 (C) 61 (D) 71 (E) 250-

The average of five distinct integers is 65. If the largest integer is 75, what is the maximum possible value of the smallest integer? (A) 1 (B) 31 (C) 61 (D) 71 (E) 250-

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
See similar textbooks
icon
Related questions
Question
the answer is not 31 because it is asking for minimum not maximum so what is the real answer? How did you get it?
The average of five distinct integers is 65. If the largest integer is 75, what is the maximum possible value of the smallest integer? (A) 1 (B) 31 (C) 61 (D) 71 (E) 250-
Transcribed Image Text:The average of five distinct integers is 65. If the largest integer is 75, what is the maximum possible value of the smallest integer? (A) 1 (B) 31 (C) 61 (D) 71 (E) 250-
Ans:- Given, the average of five distinct integers is 65. let a, b, c, d and e then tep2 ) ⇒ a+b+c+d+e 5 ⇒ a+b+c+d+e= 65x5 = 325 ⇒ a+b+c+d+e = 325 .(I) Let a be the largest integer then a= 75. From I from II are five distinct integers, Since, b, c, d and e Let b= 74, 65 75 +b+c+d+e 325 b+c+d+e=. 325-75 = 250 b+c+d+e = 250 are distinct. c= 73,d= 72 e = 31 74+73+72 +e= 250 219 += 250 - H e=250-219 Ans Hence, e = 31 is the required smallest integer.
Transcribed Image Text:Ans:- Given, the average of five distinct integers is 65. let a, b, c, d and e then tep2 ) ⇒ a+b+c+d+e 5 ⇒ a+b+c+d+e= 65x5 = 325 ⇒ a+b+c+d+e = 325 .(I) Let a be the largest integer then a= 75. From I from II are five distinct integers, Since, b, c, d and e Let b= 74, 65 75 +b+c+d+e 325 b+c+d+e=. 325-75 = 250 b+c+d+e = 250 are distinct. c= 73,d= 72 e = 31 74+73+72 +e= 250 219 += 250 - H e=250-219 Ans Hence, e = 31 is the required smallest integer.
Expert Solution
Step 1

In the question asking the maximum possible value of smallest integer.

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,
SEE MORE TEXTBOOKS