The average number of miles (in thousands) that a car's tire will function beforeneeding replacement is 68 and the standard deviation is 12. Suppose that 6randomly selected tires are tested. Round all answers to 4 decimal places wherepossible and assume a normal distribution.a. What is the distribution of X? X~ N(b. What is the distribution of T?~ N(c. If a randomly selected individual tire is tested, find the probability that thenumber of miles (in thousands) before it will need replacement is between64.8 and 71.7.d. For the 6 tires tested, find the probability that the average miles (inthousands) before need of replacement is between 64.8 and 71.7.

Given dataMean = 68Standard deviation = 12As per binomial approximationMean = np > 5 and standard…

Answered: The average number of miles (in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average American man consumes 9.7 grams of sodium each day. Suppose that the sodium consumption of American men is normally distributed with a standard deviation of 1 grams. Suppose an American man is randomly chosen. Let X = the amount of sodium consumed. Round all numeric answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N Note: this shows 2 blank spots for answers
The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
should be 4 decimal places
The average amount of money spent for lunch per person in the college cafeteria is $6.24 and the standard deviation is $2.05. Suppose that 6 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible.What is the distribution of ¯x?
The average grade for an exam is 74, the standard deviation is 7 and the grades are curved to follow a normal distribution. Find the probability that a student will get a grade from 81 to 88 Select one: O a. 0.451 b. 0.612 O c. 0.1359 O d. 0.561
On average, indoor cats live to 14 years old with a standard deviation of 2.7 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible.A. The middle 50% of indoor cats' age of death lies between what two numbers? Low: years High: years
Chebyshev's Theorem states that for any distribution of numerical data, at least 1-1/k? of the numbers lie within The percent of numbers between 88 and 112 is at least %. k standard deviations of the mean. (Round to the nearest hundredth as needed.) In a certain distribution of numbers, the mean is 100, with a standard deviation of 6. Use Chebyshev's Theorem to tell what percent of the numbers are between 88 and 112.
The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of 10. Suppose that one individual is randomly chosen. Let X=percent of fat calories. Round all answers to 4 decimal places if where possible a. What is the distribution of X? X N( b. Find the probability that a randomly selected fat calorie percent is more than 40. c. Find the minimum number for the lower quarter of percent of fat calories.
Suppose baby kittens' weights are normally distributed with a mean of 11.4 and a standard deviation of 2.1. The Z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z- Score is negative) any particular baby kitten's weight is. Find the baby kitten weight that corresponds to the following Z-scores. Use the formula Z where u is the mean, o is the standard deviation, and X is the baby kitten weight. a. Z = = 0.07, X = b. Z = 1.63, X =
Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 268 feet and a standard deviation of 38 feet. Let X be the distance in feet for a fly ball. a. What is the distribution of X? X ~ N( b. Find the probability that a randomly hit fly ball travels less than 248 feet. Round to 4 decimal places. c. Find the 70th percentile for the distribution of distance of fly balls. Round to 2 decimal places. feet

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