The average income in a certain region in 2013 was $70,000 per person per year. Suppose the standard deviation is $31,000 and the distribution is right-skewed.Suppose we take a random sample of 100 residents of the region.a. Is the sample size large enough to use the Central Limit Theorem for means? Explain.b. What are the mean and standard error of the sampling distribution?c. What is the probability that the sample mean will be more than $3,100 away from the population mean?a. Choose the correct answer below.A. Yes, it is large enough because the population standard deviation of 31,000 is larger than the sample size of 100.B. No, it is not large enough because the sample size of 100 is less than 250.C. No, it is not large enough because the sample size of 100 is not greater than 10% of the population.D. Yes, it is large enough because the sample size of 100 is greater than 25.b. The mean is $and the standard error is $(Type integers or decimals. Do not round.)c. The probability is(Round to four decimal places as needed.)

Given informationMean µ = $70,000Standard deviation σ = $31,000n = 100

The average income in a certain region in 2013 was $70,000 per person per year. Suppose the standard deviation is $31,000 and the distribution is right-skewed Suppose we take a random sample of 100 residents of the region. a. Is the sample size large enough to use the Central Limit Theorem for means? Explain. b. What are the mean and standard error of the sampling distribution? c. What is the probability that the sample mean will be more than $3,100 away from the population mean? a. Choose the correct answer below. O A. Yes, it is large enough because the population standard deviation of 31,000 is larger than the sample size of 100. O B. No, it is not large enough because the sample size of 100 is less than 250. O C. No, it is not large enough because the sample size of 100 is not greater than 10% of the population. O D. Yes, it is large enough because the sample size of 100 is greater than 25. b. The mean is $ and the standard error is $ : (Type integers or decimals. Do not round.) c. The probability is. (Round to four decimal places as needed.)

The average income in a certain region in 2013 was $70,000 per person per year. Suppose the standard deviation is $31,000 and the distribution is right-skewed Suppose we take a random sample of 100 residents of the region. a. Is the sample size large enough to use the Central Limit Theorem for means? Explain. b. What are the mean and standard error of the sampling distribution? c. What is the probability that the sample mean will be more than $3,100 away from the population mean? a. Choose the correct answer below. O A. Yes, it is large enough because the population standard deviation of 31,000 is larger than the sample size of 100. O B. No, it is not large enough because the sample size of 100 is less than 250. O C. No, it is not large enough because the sample size of 100 is not greater than 10% of the population. O D. Yes, it is large enough because the sample size of 100 is greater than 25. b. The mean is $ and the standard error is $ : (Type integers or decimals. Do not round.) c. The probability is. (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

State Ho and H, in words and in symbols. Then determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Explain your reasoning. Sketch a normal sampling distribution and shade the area for the P-value. A report claims that lung cancer accounts for at least 38% of all cancer diagnoses. State the null hypothesis in words and in symbols. The null hypothesis expressed in words is the proportion of cancer diagnoses attributable to lung cancer is at least 0.38. The null 0.38 hypothesis is expressed symbolically as H,: p (Type integers or decimals. Do not round.) State the alternative hypothesis in words and in symbols. The alternative hypothesis expressed in words is the proportion of cancer diagnoses attributable to lung cancer is less than 0.38. The alternative hypothesis is expressed symbolically as H3: p (Type integers or decimals. Do not round.) 0.38 The hypothesis test is V because the alternative hypothesis contains Help me solve this View an example Get more…
Solve the problem.Assume that mountain lions' weights are normally distributed with a mean of 62.6 kilograms and a standard deviation of 2.6 kilograms. If 70 mountain lions are randomly selected, find the probability that they have a mean weight between 61.9 kilograms and 62.8 pounds.
Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. Find the percentage of buyers who paid between $148,200 and $151,800 if the standard deviation is $1800. Group of answer choices 99.7% 34%
The annual salary for one particular occupation is normally distributed, with a mean of about $123,000 and a standard deviation of about $20,000. Random samples of 44 are drawn from this population, and the mean of each sample is determined. Find the mean and standard deviation of the sampling distribution of these sample means. Then, sketch a graph of the sampling distribution.
PRACTICE! A population consists of five values: 2, 3, 4, 5, and 6. A sample of size 2 is to be taken from the population. How many samples are possible? Construct the sampling distribution of the sample means. Compute for the mean and standard deviation of the sampling distribution.
Suppose that 65% of the 310,000 citizens in a county are registered to vote. A non-profit organization takes a simple random sample of 100 of these citizens and finds that 67% of those sampled are registered to vote. The organization plans on taking repeated samples. What is the mean and the standard deviation of the sampling distribution of the proportion of citizens who are registered to vote?
Suppose the price for pomegranates in NYC have a mean of $1.25 with a standard deviation of $0.15. Suppose you sample 1 pomegranate for different stores in NYC for a total of 50 pomegranates. What is the resulting sampling distribution (mean, standard deviation) for this sample? Assume a random sample. a. None of these b. ($0.18, $0.02) c. ($1.25, $0.02) d. Whatever the mean and standard deviation of the sample is. e. ($1.25, $0.15)
20. Sampling distribution. From 1975 through 2016, the mean gain of the Down jones industrial average was 470. A random sample of 32 years is selected from population. What is the probability that the mean gain for the sample was between 200 and 500. The standard deviation of population is 1215
In a certain region, the mean annual salary for electricians is $58,650. Let x be a random variable that represents an electrician's salary. Assume the standard deviation is $1420. If a random sample of 50 electricians is selected, what is the probability that the sample mean is greater than $59,000? A. 0.041 B. 0.403 C. 0.038 D. 0139
A. The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly. Find the probability that the sum of the 40 values is less than 6,900. (Round your answer to four decimal places.) B. The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly. Find the sum that is one standard deviation below the mean of the sums. (Round your answer to two decimal places.) C. The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly. Find the sum that is 1.4 standard deviations below the mean of the sums. (Round your answer to two decimal places.)
A study shows that the normal time that a customer occupied a table in a fine dine restaurant is 1.2 hours with a standard deviation of 0.4 hour. A food entrepreneur wants to find the probability that customers occupying 25 tables would have an average time of less than 1 hour. Question: 1. What is the value of the standard deviation of the sampling distribution? A. 0.08 B. 0.4 C. 1.2 D. 1
Dut Trenta and his friends play a game where they will win the amount indicated in the boxes they will pick. In Box 1, 2, 3, 4, 5, and 6, the prizes are 500, 1000, 500, 800, 1500, and 2000 respectively. A random sample of 3 boxes were selected without replacement. Let X be the amount indicated inside a box. a. Find the sampling distribution of ?. b. Find the mean and standard deviation of ?.