The average human body contains 5.80 L of blood with aFe2+ concentration of 2.10x10-5 M . If a person ingests8.00 mL of 18.0 mM NACN, what percentage of iron(II)in the blood would be sequestered by the cyanide ion?Express the percentage numerically.• View Available Hint(s)ΑΣφ?20.69% Fe2+2+From the value Kf = 1.2 x 10° for Ni(NH3)6calculate the concentration of NH3 required to justdissolve 0.026 mol of NiC2 O4 (Ksp = 4 x 10-10 ) in1.00 L of solution. (Hint: You can neglect the hydrolysis ofC2042- because the solution will be quite basic.)Express your answer using two significant figures.ΑΣφ[NH3]1.41MSubmitPrevious Answers Request Answer

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The average human body contains 5.80 L of blood with a Fe2+ concentration of 2.10x10-5 M . If a person ingests 8.00 mL of 18.0 mM NACN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically. • View Available Hint(s) ΑΣφ ? 20.69 % Fe2+

The average human body contains 5.80 L of blood with a Fe2+ concentration of 2.10x10-5 M . If a person ingests 8.00 mL of 18.0 mM NACN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically. • View Available Hint(s) ΑΣφ ? 20.69 % Fe2+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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