The average fruit fly will lay 420 eggs into rotting fruit. A biologist wants to see if the average will be fewerfor flies that have a certain gene modified. The data below shows the number of eggs that were laid intorotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population isnormal.392, 396, 409, 434, 401, 393, 394, 420, 436, 435, 410, 430, 431, 416, 403What can be concluded at the the a = 0.10 level of significance level of significance?a. For this study, we should useSelect an answerb. The null and alternative hypotheses would be:Но:?Select an answerH1:?Select an answerc. The test statistic | ? ▼(please show your answer to 3 decimal places.)%3Dd. The p-value =(Please show your answer to 4 decimal places.)e. The p-value is (?f. Based on this, we should | Select an answerthe null hypothesis.g. Thus, the final conclusion is that ...The data suggest that the population mean number of eggs that fruit flies with this genemodified will lay in rotting fruit is not significantly less than 420 at a = 0.10, so there isinsufficient evidence to conclude that the population mean number of eggs that fruit flies withthis gene modified will lay in rotting fruit is less than 420.%3DThe data suggest the populaton mean is significantly less than 420 at a = 0.10, so there issufficient evidence to conclude that the population mean number of eggs that fruit flies with thisgene modified will lay in rotting fruit is less than 420.The data suggest the population mean is not significantly less than 420 at a = 0.10, so there issufficient evidence to conclude that the population mean number of eggs that fruit flies with thisgene modified will lay in rotting fruit is equal to 420.

Name: The average fruit fly will lay 420 eggs into rotting fruit. A biologi
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: The average fruit fly will lay 420 eggs into rotting fruit. A biologist wants to see if the average will be fewerfor flies that have a certain gene modified. The data below shows the number of eggs that were laid intorotting fruit by several fruit f

From the given data: x¯=∑xn=620015=413.33s=16.6548 n=15 a) For this study, we should use…

Math

Statistics

The average fruit fly will lay 420 eggs into rotting fruit. A biologist wants to see if the average will be fewer for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 396, 409, 434, 401, 393, 394, 420, 436, 435, 410, 430, 431, 416, 403

The average fruit fly will lay 420 eggs into rotting fruit. A biologist wants to see if the average will be fewer for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 396, 409, 434, 401, 393, 394, 420, 436, 435, 410, 430, 431, 416, 403

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

About 3% of the population has a particular genetic mutation. 900 people are randomly selected.Find the mean for the number of people with the genetic mutation in such groups of 900.
About 2% of the population has a particular genetic mutation. 800 people are randomly selected. Find the mean for the number of people with the genetic mutation in such groups of 800.
The mode of the data 24, 22, 28, 24, 34, 31, 24 is O 24 O 28 O 22 O 31 O 34
Determine if the data are approximately normally distributed. Please use R software.
The data show the population (in thousands) for a recent year of a sample of cities in South Carolina. 26 26 15 29 69 21 30 29 13 26 20 38 85 19 19 23 29 25 111 47 30 49 108 30 38 Send data to Excel
About 2% of the population has a particular genetic mutation. 900 people are randomly selected. Find the mean for the number of people with the genetic mutation in such groups of 900.
About 5% of the population has a particular genetic mutation. 600 people are randomly selected.Find the mean for the number of people with the genetic mutation in such groups of 600.
The following items represent the number of birds observed at a given feeder over the past several days. What is the median number of birds to visit that feeder? 66, 9, 44, 25, 37, 94, 92, 26
For a set of data arranged or sorted in numerical order, the value of the observation in the center is called the weighted mean. Group startsTrue or FalseTrue, unselectedFalse, unselectedGroup ends
Find the variance. Hope you'll do a step-by-step olution.
About 1% of the population has a particular genetic mutation. 200 people are randomly selected. Find the mean for the number of people with genetic mutation in such group of 200.