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The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 387, 378, 365, 392, 393, 374, 401, 396, 379, 374, 392, 390 What can be concluded at the the ax = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H₁: Select an answer c. The test statistic ? ✓= (please show your answer to 3 decimal places.)

The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 387, 378, 365, 392, 393, 374, 401, 396, 379, 374, 392, 390 What can be concluded at the the ax = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H₁: Select an answer c. The test statistic ? ✓= (please show your answer to 3 decimal places.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 387, 378, 365, 392, 393, 374, 401, 396, 379, 374, 392, 390 What can be concluded at the the ax = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: H₁: ?v Select an answer Select an answer ✓ c. The test statistic d. The p-value = e. The p-value is ? ✓ α f. Based on this, we should [Select an answer the null hypothesis. g. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is not significantly more than 377 at a = 0.05, so there is insufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 377. O The data suggest the population mean is not significantly more than 377 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is equal to 377. O The data suggest the populaton mean is significantly more than 377 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 377.
Transcribed Image Text:The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 392, 387, 378, 365, 392, 393, 374, 401, 396, 379, 374, 392, 390 What can be concluded at the the ax = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: H₁: ?v Select an answer Select an answer ✓ c. The test statistic d. The p-value = e. The p-value is ? ✓ α f. Based on this, we should [Select an answer the null hypothesis. g. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is not significantly more than 377 at a = 0.05, so there is insufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 377. O The data suggest the population mean is not significantly more than 377 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is equal to 377. O The data suggest the populaton mean is significantly more than 377 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 377.
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