The average daily volume of a computer stock in 2011 was μ = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2018 is different from the 2011level. Based on a random sample of 30 trading days in 2018, he finds the sample mean to be 26.8 million shares, with a standard deviation of s = 11.3 million shares. Test the hypotheses byconstructing a 95% confidence interval. Complete parts (a) through (c) below.(a) State the hypotheses for the test.Ho:H₁:(b) Construct a 95% confidence interval about the sample mean of stocks traded in 2018.With 95% confidence, the mean stock volume in 2018 is between million shares and(Round to three decimal places as needed.)(c) Will the researcher reject the null hypothesis?35.1 million shares35.1 million sharesmillion shares.A. Reject the null hypothesis because µ = 35.1 million shares falls in the confidence interval.B. Do not reject the null hypothesis because µ = 35.1 million shares does not fall in the confidence interval.C. Do not reject the null hypothesis because µ = 35.1 million shares falls in the confidence interval.D. Reject the null hypothesis because μ = 35.1 million shares does not fall in the confidence interval.

The average daily volume of a computer stock in 2011 was µ = 35.1 million shares, according to a…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Nielsen Media Research conducted a study of household television viewing time during the 7PM to 10PM time period (This is known as Prime Time). The average weekly time spent watching was 785 minutes. This was based off 600 randomly selected households. Based upon past studies the population standard deviation is known to be 65 minutes. Develop an 80% confidence interval for the average time Americans watched prime-time TV this week.
Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients. The average LOS in Canada is 4.6 days. A random sample of 18 hospitals in one province had a mean LOS of 3.8 days and a standard deviation of 1.7 days. Assume that the sampled population is approximately normal. You are to construct a 95% confidence interval to see if the population mean of 4.6 days is true. Answer the followings: a. What is/are the critical value(s)? b. What is the margin of error? c. Identify the 95% confidence interval for the mean. d. Interpret the interval in terms of this application. Circle the letter of the correct answer below. A. The state can be 95% confident that its mean LOS is within this interval. B. The state can be 5% confident that its mean LOS is within this interval. C. The state can be 95% confident that its mean LOS is outside this interval. D. The state can be 95% confident that its mean LOS is 3.8 days.…
The average daily volume of a computer stock in 2011 was μ = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2018 is different from the 2011 level. Based on a random sample of 40 trading days in 2018, he finds the sample mean to be 31.3 million shares, with a standard deviation of s= 13.1 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through (c) below. www. (a) State the hypotheses for the test. Ho ▼ 35.1 million shares ▼ 35.1 million shares Help me solve this View an example Get more help. Clear all Check answer Type here to search 1:43 PM 6/18/2022 & 3 1 H₁. ? 4 R F 96 5 B 7 U 8 1 M 9 K a ? 95°F Mostly sunny SC
A random sample of 21 lunch orders at Noodles & Company showed a mean bill of $13.54 with a standard deviation of $6.45. Find the 98 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) The 98% confidence interval is from _____to______
The average daily volume of a computer stock in 2011 was μ=35.1million shares, according to a reliable source. A stock analyst believes that the stock volume in 2018 is different from the 2011 level. Based on a random sample of 30 trading days in 2018, he finds the sample mean to be 29.1 million shares, with a standard deviation of s=13 million shares. Test the hypotheses by constructing a 95%confidence interval. Complete parts (a) through (c) below. ( B ) Construct a 95% confidence interval about the sample mean of stocks traded in 2018. With 95% confidence, the mean stock volume in 2018 is between
In the 2018 General Social Survey, a random sample of 1666 adults in the U.S. was asked how old they were when they had their first child. The average age at first birth for this sample was 24.3, with a standard deviation of 5.74. Use these data to calculate a 95% confidence interval for the mean age at first birth in the population, and answer the following questions based on those calculations. What is the lower bound for this confidence interval?
The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 30 trading days in 2014, he finds the sample mean to be 29.4 million shares, with a standard deviation of s= 13 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through (c) below. (a) State the hypotheses for the test. Ho: 35.1 million shares 35.1 million shares ad (b) Construct a 95% confidence interval about the sample mean of stocks traded in 2014. ud The lower bound is million shares. The upper bound is million shares. irad (Round to three decimal places as needed.) (c) Will the researcher reject the null hypothesis? eTex O A. Reject the null hypothesis because u = 35.1 million shares does not fall in the confidence interval. HTM
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