The average amount of money spent for lunch per person in the college cafeteria is $5.85 and the standard deviation is $2.52. Suppose that 46 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible. a. What is the distribution of X? X N( b. What is the distribution of a? a - N( c. For a single randomly selected lunch patron, find the probability that this patron's lunch cost is between $5.9226 and $6.3584.
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please help with a,b,c

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