The average age of construction workers is 32 years with a standard deviation of 5 years. If a construction company employs 25 workers, find the probability that the average age of the group is greater than 33.9 years old. If this is the case, would it be safe to assume that the construction workers in this group are generally much older than average? Assume that the sample is taken from a large population and the correction factor can be ignored. Give your final answer as a percent rounded to two

Q: Find the probability that the sample mean is between 40 and 50. Sample size is 36 are drawn randomly…

A: From the provided information, Mean (µ) = 45 Standard deviation (σ) = 20 X~N (45, 20) Sample size…

Q: CNNBC recently reported that the mean annual cost of auto insurance is $962. Assume the standard…

A: Given information: The mean annual cost of auto insurance is $962. The standard deviation is $190.…

Q: The average production cost for major movies is 69 million dollars and the standard deviation is 18…

A: Mean = 69 Standard deviation = 18 Sample size = 39

Q: A population has a mean of 200 and a standard deviation of 25. A sample of 64 observations will be…

A: We have to find out given probabiity..

Q: 95% of 80 freshman history students scored between 70% and 80% on a take home quiz. If this data is…

A: Given,  n=80 α= (1-0.95) =0.05 Let X denote the score of freshmen. As per t-distribution table, the…

Q: Tiger Woods hits an average driver 287.2 yards with a standard deviation of 24.6 yards. What is the…

A: The probability value is calculate by means of standard normal variate with the random variable,…

Q: If the mean of a list of numbers is 16.7 and the standard deviation is 0,

A: Mean is a measure of central tendency. It is one of the most important measures to find out around…

Q: A particular fruit's weights are normally distributed, with a mean of 222 grams and a standard…

A: Solution: Let X be the  fruit's weights are normally distributed with mean 222 grams and standard…

Q: A researcher showed the mean of weights of college football players to be 200 pounds with a standard…

A:

Q: The average price of a college math textbook is $151 and the standard deviation is $26. Suppose that…

A: Given Data: Let X represent the random variable X~ Normal (151, 262)   n=42 Therefore, X¯~ Normal…

Q: You want to determine the probability that when seven consumers are randomly selected, exactly two…

A: 1. n = 7, x = 2, p = 0.45, q = 0.552. Mean, μ = 3.15    Standard Deviation, σ = 1.31623. P(X = 2) =…

Q: High school girls average 80 text messages daily. Assume the population standard deviation is 15…

A: Given information:

Q: A particular fruit's weights are normally distributed, with a mean of 256 grams and a standard…

A: given data  normal distribution μ = 256σ = 29n = 8P(x¯>z) = 0.17

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: A certain video game has 72% chance of sucess. During summer vacation a person plays 12 games a day.…

A: In question, Given that A certain video game has 72% chance of sucess. During summer vacation a…

Q: ind the probability that a voice recorder will last between 2.8 and 6 years. Find the 70th…

A: Let X denote the voice recorder and it follows normal distribution with mean of μ=4.1 years and…

Q: A particular fruit's weights are normally distributed, with a mean of 207 grams and a standard…

A: It is given that the fruit weights have a normal distribution with mean 207 grams and standard…

Q: Suppose the probability a patient will recover from a disease following medication is 0.7. In a…

A: Given : the probability a patient will recover from a disease following medication is 0.7.  In a…

Q: A 4x2x3 ANOVA was conducted. How many main effects should be tested? Answer Choices:  2   3   4…

A: There are in all 3 factors A, B and C each with levels 4, 2 and 3 Thus, the total number of main…

Q: 500 freshmen at Arundel University took part in a math comprehension test. The scores were normally…

A: From the provided information, Mean (µ) = 75 Standard deviation (σ) = 7 Let X be a random variable…

Q: Gülce spends 8 hours for Roblox per day. If the probability of spending less than 6 hours in a…

A:

Q: The average score of all golfers for a particular course has a mean of 64 and a standard deviation…

A:

Q: A normal population had a mean of 70 and a standard deviation of 12. You select a random sample of…

A: μ = 70σ = 12n = 9P(x¯>73) = ?

Q: The salary for workers at a company are normally distributed with a mean of $60,000 and a standard…

A:

Q: The amount that people pay for their cellphone service is normally distributed with a mean of $136…

A:

Q: The length of a fully grown hibiscus plant is normally distributed and has a mean of 35cm and a…

A: Given that, The random variable X is length of fully grown hibiscus plant. It is normally…

Q: Refer to the accompanying table, which describes results from groups of 8 births from 8 different…

A: xP(x)00.00310.02620.11830.21240.27450.22760.10870.02780.005

Q: normal population had a mean of 70 and a standard deviation of 12. You select a random sample of 9.…

A: given data normal distributionμ = 70σ = 12n = 9 P(x¯<66) = ?

Q: All the houses in Stanton county have a mean size of 1650 square feet with a standard deviation of…

A:

Q: The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard…

A: Z= x¯-μσn~N(0,1) n  = 36 , x¯ = 98.6 , μ = 98.6 , σ = 0.6

Q: The percent fo Coloradans that own a Subaru is 56%. If you were to take a random sample of size 70,…

A: We have given that,  Let X be the random variable from binomial distribution with probability (p) =…

Q: Song length varies from genre to genre. Brian wonders if there is a difference in the length of…

A: Answer:- Given, For Country songs  Sample size, n1 = 50 , Sample mean ,X̄1 = 3.44 minutes and…

Q: The mean is μ = girl(s). (Round to one decimal place as needed.) The standard deviation is o =…

A: Number of girls xP(x)00.00310.03220.11430.22740.26650.21460.11270.02980.003

Q: A manufacturing company produces electric insulators. You define the variable of interest as the…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: Suppose that we know that 33.8% of the people born in the United States between 1936 and 1951 have…

A:

Q: Directions: Read and answer the given problem. Provided for your solutions. 1. Consider tossing an…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Solve the problem. Assume that mountain lions' weights are normally distributed with a mean of 62.6…

A: We have given that,  X be the random variable from normal distribution with mean (μ) = 62.6 ,…

Q: The electric bills for all households in a large city have the normal distribution with a mean of…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 284 grams and a standard…

A: From the provided information, Mean (µ) = 284 grams Standard deviation (σ) = 32 grams X~N (284, 32)

Q: A population has a mean of 84 and a standard deviation of 12. A sample of 36 observations be taken.…

A: Given: Population mean μ = 84 Population standard deviation σ = 12 Sample size n = 36

Q: According to government data the probability that an adult was never in a museum is 11%, in a random…

A: Givenp=0.11sample size(n)=20Let "x" be the no.that were never in a…

Q: About 75% of all female heart transplant patients will survive for at least 3 years. Sixty female…

A:

Q: A grocer finds that the cantaloupes in his store have weights with mean 0.7 kg and standard…

A: Given, Mean weight of cantaloupes is 700 gm. Standard deviation is 53 gm

Q: In a survey, 80% of the voters support a particular referendum.  If 30 voters are chosen, find the…

A: Number of voters(n)=30∵80% of the voters support a particular referendum i..e. p=0.80

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.