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The auxiliary equit of the given diff- is m² + 6m +8 = 0 2 m² + ym + 2m +8=0 m (m+4) +2 (m+4) = 0 2 (m+4) (m+²) 20 =) m = -4₁ m = -2 How did he get the value inside the circle

The auxiliary equit of the given diff- is m² + 6m +8 = 0 2 m² + ym + 2m +8=0 m (m+4) +2 (m+4) = 0 2 (m+4) (m+²) 20 =) m = -4₁ m = -2 How did he get the value inside the circle

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The auxiliary equit of the given diff- is m² + 6m +8 = 0 2 m² tym+ 2m +8=0 2 m (m+4) +2(m+y) = 0 2 (m+4) (m+₂) 20 m = -4₁ m² - 2 How did he get the value inside the circle
Transcribed Image Text:The auxiliary equit of the given diff- is m² + 6m +8 = 0 2 m² tym+ 2m +8=0 2 m (m+4) +2(m+y) = 0 2 (m+4) (m+₂) 20 m = -4₁ m² - 2 How did he get the value inside the circle
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