The auxiliary equation of y"-49"-49² +6 Y is f² ²3 ²³ 45²_-45+16=0. The auxiliary. equation hels a root in the interval [-0.75, 3.75] 3 Let For=r²³-4²2²-4r +16, so that the reats of the auxillary auxiliary equation can be determined by solving For=0
The auxiliary equation of y"-49"-49² +6 Y is f² ²3 ²³ 45²_-45+16=0. The auxiliary. equation hels a root in the interval [-0.75, 3.75] 3 Let For=r²³-4²2²-4r +16, so that the reats of the auxillary auxiliary equation can be determined by solving For=0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The auxiliary equation of y" - 40"-4 4² +16 Y = 0
is f² r² r²³_-_ 4r²_45+16=0. The auxiliary
equation hels a root in the interval [-0.75, 3.75]
3
Let For) = r²³²_4²_4r +16, so that the reats of the
auxillary auxiliary equation can be determined
by solving For=C
Then, applying Four iterations of the Bisection method
to for), using the initial approximations (1= -0.75
and r₂ = 3.75, gives the following approximation
For the reet in [-0.75, 3.7518
Гз
(1)
133)
(
3
(2)
(4)
B
=
=
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06089eb2-ff0d-4c09-8152-ab59813eefd5%2Faf5a6aa2-bb3d-4db3-9838-900f97f9979e%2Fogqqsys_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The auxiliary equation of y" - 40"-4 4² +16 Y = 0
is f² r² r²³_-_ 4r²_45+16=0. The auxiliary
equation hels a root in the interval [-0.75, 3.75]
3
Let For) = r²³²_4²_4r +16, so that the reats of the
auxillary auxiliary equation can be determined
by solving For=C
Then, applying Four iterations of the Bisection method
to for), using the initial approximations (1= -0.75
and r₂ = 3.75, gives the following approximation
For the reet in [-0.75, 3.7518
Гз
(1)
133)
(
3
(2)
(4)
B
=
=
=
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