The autoionization of water at 25°C can be expressed as H,0(l) → H*(aq) + ОН (ад); Кw %3D 10-14 13. Using appropriate calculations, (a) Determine if this reaction is exothermic or endothermic. (b) Show whether this reaction will occur spontaneously. (c) Using the thermodynamics of the reaction, explain how Kw will change at temperatures (1) greater than 25°C and (2) less than 25°C. Species дн? (кJ/mol) AS: (J/K-mol) AG: (kJ/mol) H2O(g) H*(aq) оН ад) -241.8 188.71 -228.6 0.00 0.00 0.00 -230.0 -10.75 -157.2 H2O(1) -237.18 -285.8 69.91 O(aq) 249.17 160.95 231.75
The autoionization of water at 25°C can be expressed as H,0(l) → H*(aq) + ОН (ад); Кw %3D 10-14 13. Using appropriate calculations, (a) Determine if this reaction is exothermic or endothermic. (b) Show whether this reaction will occur spontaneously. (c) Using the thermodynamics of the reaction, explain how Kw will change at temperatures (1) greater than 25°C and (2) less than 25°C. Species дн? (кJ/mol) AS: (J/K-mol) AG: (kJ/mol) H2O(g) H*(aq) оН ад) -241.8 188.71 -228.6 0.00 0.00 0.00 -230.0 -10.75 -157.2 H2O(1) -237.18 -285.8 69.91 O(aq) 249.17 160.95 231.75
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The autoionization of water at 25°C can be expressed as H,0(l) → H*(aq) +
ОН (ад); Кw %3D 10-14
13.
Using appropriate calculations,
(a) Determine if this reaction is exothermic or endothermic.
(b) Show whether this reaction will occur spontaneously.
(c) Using the thermodynamics of the reaction, explain how Kw will change at
temperatures (1) greater than 25°C and (2) less than 25°C.
Species
дн? (кJ/mol)
AS: (J/K-mol)
AG: (kJ/mol)
H2O(g)
H*(aq)
оН ад)
-241.8
188.71
-228.6
0.00
0.00
0.00
-230.0
-10.75
-157.2
H2O(1)
-237.18
-285.8
69.91
O(aq)
249.17
160.95
231.75
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