The atomic radius of lead is 0.238 nm. If it forms a face-centered cubic crystalline structure, what is its density (in g/cm³)? Atomic weight of head=207.2 g/mol

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The atomic radius of lead is 0.238 nm. If it forms a face-centered cubic crystalline
m³)? Atomic weight of lead=207.2 g/mol
structure, what is its density (in g/cm3
Express your answer in two decimal places.
Transcribed Image Text:The atomic radius of lead is 0.238 nm. If it forms a face-centered cubic crystalline m³)? Atomic weight of lead=207.2 g/mol structure, what is its density (in g/cm3 Express your answer in two decimal places.
P:
nA
VCNA
Where: p density (g/cm³)
n = no. of atoms/ unit cell
A = atomic weight (g/mol)
Important
conversion factors
1 cm = 107 nm
1 cm = 10¹⁰ pm
1 cm = 10⁰ Å
1 nm = 10 Å
Vc = volume / unit cell (cm³/unit cell) = a³
NA = Avogadro's number = 6.022x10²3 atoms/mol
Transcribed Image Text:P: nA VCNA Where: p density (g/cm³) n = no. of atoms/ unit cell A = atomic weight (g/mol) Important conversion factors 1 cm = 107 nm 1 cm = 10¹⁰ pm 1 cm = 10⁰ Å 1 nm = 10 Å Vc = volume / unit cell (cm³/unit cell) = a³ NA = Avogadro's number = 6.022x10²3 atoms/mol
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