The Associated Press (October 9, 2002) reported that in a survey of 4722 American youngsters aged 6 to 19, 15% were seriously overweight (a body mass index of at least 30; this index is a measure of weight relative to height). Calculate and interpret a confidence interval using a 99% confidence level for the proportion of all American youngsters who are seriously overweight.

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

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Q: In a survey of 650 randomly selected U.S. males ages 18-64, 396 say they have gone to the dentist in…

A: Given,n=650x=396p^=xnp^=396650=0.6091-p^=1-0.609=0.391α=1-0.90=0.1α2=0.05Z0.05=1.645     (from…

Q: what would be the 90% confidence interval of the true proportion of young adults who have received…

A: Given that sample size is n = 190 And the sample proportion is 70% = 0.7 At 90% confidence level,…

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = 34, standard deviation (s)=6 and sample size (n) = 10 Then,…

Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: The Centers for Disease Control reported the percentage of people 18 years of age and older who…

A: a) The sample size can be estimated as follows: n=ze2p(1-p)where, z = z scoree = errorp =…

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

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Q: We are trying to estimate the average lifespan of all Neanderthal humans who lived 100,000 years…

A: Given: Sample of 56 skeletons from caves and construct a 95% confidence interval for their…

Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

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Q: In a survey of 3115 adults aged 57 through 85​ years, it was found that 86.1​% of them used at…

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Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: On September 14, 2000, a cross-sectional survey of 24,000 residents of a western state revealed that…

A: Given: n = 24000 Number of tuberculosis cases X = 145 Proportion p^ = Xn Formula Used: Confidence…

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Using excel formula “=T.INV(1-(0.2/2),22)”, the critical value of 80% confidence level is 1.321.

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that  Sample mean = 46 Sample standard deviation = 10 Sample size = 28

Q: In a survey, 24 people were asked how much they spent on their child's last birthday gift. The…

A: From the available information, Sample size, n =24 Sample mean, x = 31 Sample standard deviation, s…

Q: A survey of 20 people asked, “If you’ve ever been married, how old were you when you were first…

A:

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean = x̅ = 46 Sample size = n = 23 Sample S.D = s = 12 Standard Error = s/√n  = 12/√23…

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: The Nellie Mae organization conducts an extensive annual study of credit card usage by college…

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Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: See the handwritten solution

Q: In 2015 as part of the General Social Survey, 1131 randomly selected American adults responded to…

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Q: survey conducted by Gallup in 2020 asked 1,102 randomly selected U.S. adults, "What do you think is…

A: We have given that  Sample size n=1102 90% confidence interval.  = (0.6773, 0.7227)

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: Given information- Sample size, n = 14 Mean, x-bar = $32 Standard deviation, s = $20 Confidence…

Q: Listed below are the amounts of net worth​ (in millions of​ dollars) of the ten wealthiest…

A: Sample size(n)=10sample mean(x¯)=171standard deviation(s)=33.79020degrees of…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.