The assistant adjusts the tension in the same piano string, and a beat frequency of 4.00 Hz is heard when the note and the tuning fork are struck at the same time. (a) Find the two possible frequencies of the string. flower = Hz fhigher Hz (b) Assume the actual string frequency is the higher frequency. If the piano tuner runs away from the piano at 3.59 m/s while holding the vibrating tuning fork, what beat frequency does he hear? f = Hz
The assistant adjusts the tension in the same piano string, and a beat frequency of 4.00 Hz is heard when the note and the tuning fork are struck at the same time. (a) Find the two possible frequencies of the string. flower = Hz fhigher Hz (b) Assume the actual string frequency is the higher frequency. If the piano tuner runs away from the piano at 3.59 m/s while holding the vibrating tuning fork, what beat frequency does he hear? f = Hz
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Transcribed Image Text:The assistant adjusts the tension in the same piano string, and a beat frequency of 4.00 Hz is heard when
the note and the tuning fork are struck at the same time.
(a) Find the two possible frequencies of the string.
flower =
Hz
fhigher
Hz
(b) Assume the actual string frequency is the higher frequency. If the piano tuner runs away from
the piano at 3.59 m/s while holding the vibrating tuning fork, what beat frequency does he hear?
f =
Hz
(c) What beat frequency does the assistant on the bench hear? Use 343 m/s for the speed of
sound.
f =
Hz
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