The article "Low-Temperature Heat Capacity and Thermodynamic Properties of 1,1,1- trifluoro-2,2-dichloroethane" (R. Varushchenko and A. Druzhinina, Fluid Phase Equilibria, 2002-109-119) descrībes an experiment in which samples of Freon R-123 were melted in a calorimeter. Various quantities of energy were supplied to the calorimeter for melting. The equilibrium melting temperatures () and fractions melted (f) were measured. The least- squares line was fit to the model t= R, + B,(1/f) + Ewhere 1/f is the reciprocal fraction. The results of the fit are as follows. The regression equation is Temperature = 145.74 - 0.052 Reciprocal Frac Predictor Constant Recip Frac -0.05180 0.00226-22.906 0.000 S= 0.019516R-Sq = 97.6% R-Sq(adj) = 97.4% Analysis of Variance Source DF Regressiop 1 0.200 0.200524.700.000 Residual Елог т Р 145.736 0.00848 17190.10.000 Coef SE Coef MS F P 130.004950.000381 Total 14 0.205 a. Estimate the temperature at which half of the sample will melt (i.e., f= 12). Can you determine the corelation coefficient between eguilibrium temperature and reciprocal of the fraction melted from this output? If so, determine it. If not, explain what additional information is needed. The triple-point temperature is the lowest temperature at which the whole sample will melt (ie, f= 1). Estimate the triple-point temperature.

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The article "Low-Temperature Heat Capacity and Thermodynamic Properties of 1,1,1-
trifluoro-2,2-dichloroethane" (R. Varushchenko and A. Druzhinina, Fluid Phase Equilibria,
2002-109-119) descrībes an experiment in which samples of Freon R-123 were melted in a
calorimeter. Various quantities of energy were supplied to the calorimeter for melting. The
equilibrium melting temperatures () and fractions melted (f) were measured. The least-
squares line was fit to the model t= R, + B,(1/f) + Ewhere 1/f is the reciprocal fraction. The
results of the fit are as follows.
The regression equation is
Temperature = 145.74 - 0.052 Reciprocal Frac
Predictor
Constant
Recip Frac -0.05180 0.00226-22.906 0.000
S= 0.019516R-Sq = 97.6% R-Sq(adj) = 97.4%
Analysis of Variance
Source DF
Regressiop 1 0.200 0.200524.700.000
Residual
Елог
т Р
145.736 0.00848 17190.10.000
Coef SE Coef
MS
F P
130.004950.000381
Total
14 0.205
a. Estimate the temperature at which half of the sample will melt (i.e., f= 12).
Can you determine the corelation coefficient between eguilibrium temperature and
reciprocal of the fraction melted from this output? If so, determine it. If not, explain
what additional information is needed.
The triple-point temperature is the lowest temperature at which the whole sample will
melt (ie, f= 1). Estimate the triple-point temperature.
Transcribed Image Text:The article "Low-Temperature Heat Capacity and Thermodynamic Properties of 1,1,1- trifluoro-2,2-dichloroethane" (R. Varushchenko and A. Druzhinina, Fluid Phase Equilibria, 2002-109-119) descrībes an experiment in which samples of Freon R-123 were melted in a calorimeter. Various quantities of energy were supplied to the calorimeter for melting. The equilibrium melting temperatures () and fractions melted (f) were measured. The least- squares line was fit to the model t= R, + B,(1/f) + Ewhere 1/f is the reciprocal fraction. The results of the fit are as follows. The regression equation is Temperature = 145.74 - 0.052 Reciprocal Frac Predictor Constant Recip Frac -0.05180 0.00226-22.906 0.000 S= 0.019516R-Sq = 97.6% R-Sq(adj) = 97.4% Analysis of Variance Source DF Regressiop 1 0.200 0.200524.700.000 Residual Елог т Р 145.736 0.00848 17190.10.000 Coef SE Coef MS F P 130.004950.000381 Total 14 0.205 a. Estimate the temperature at which half of the sample will melt (i.e., f= 12). Can you determine the corelation coefficient between eguilibrium temperature and reciprocal of the fraction melted from this output? If so, determine it. If not, explain what additional information is needed. The triple-point temperature is the lowest temperature at which the whole sample will melt (ie, f= 1). Estimate the triple-point temperature.
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