The article "A Probabilistic Analysis of Dissolved Oxygen-Biochemical Oxygen Demand Relationship in Streams" (J. Water Resources Control Fed., 1969: 73-90) reported data on the rate of oxygenation in streams in a certain region. The sample mean and standard deviation were computed as a = 0.173 and s= 0.066, respectively. We would like to know if a normal distribution could be a reasonable model for the data. To do this, we have partitioned the quantitative variable into 5 discrete regions and counted the number of streams observed to have oxygenation rates in the given interval. First determine the probability of falling into each region if the normal distribution is the appropriate model. Then use those probabilities with the expected counts to conduct a Chi-squared goodness of fit test. Use a = 0.05. Frequency 12 20 23 15 Rate (per day) Below .100 .100 below.150 .150 below.200 .200 - below.250 .250 or more 13

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The article "A Probabilistic Analysis of Dissolved Oxygen-Biochemical Oxygen Demand Relationship in Streams"
(J. Water Resources Control Fed., 1969: 73-90) reported data on the rate of oxygenation in streams in a certain
region. The sample mean and standard deviation were computed as = 0.173 and s= 0.066, respectively.
We would like to know if a normal distribution could be a reasonable model for the data. To do this, we have
partitioned the quantitative variable into 5 discrete regions and counted the number of streams observed to
have oxygenation rates in the given interval. First determine the probability of falling into each region if the
normal distribution is the appropriate model. Then use those probabilities with the expected counts to conduct
a Chi-squared goodness of fit test. Use a = 0.05.
Frequency
12
20
23
15
13
Rate (per day)
Below .100
.100 below.150
.150 - below.200
.200 - below .250
.250 or more
Transcribed Image Text:The article "A Probabilistic Analysis of Dissolved Oxygen-Biochemical Oxygen Demand Relationship in Streams" (J. Water Resources Control Fed., 1969: 73-90) reported data on the rate of oxygenation in streams in a certain region. The sample mean and standard deviation were computed as = 0.173 and s= 0.066, respectively. We would like to know if a normal distribution could be a reasonable model for the data. To do this, we have partitioned the quantitative variable into 5 discrete regions and counted the number of streams observed to have oxygenation rates in the given interval. First determine the probability of falling into each region if the normal distribution is the appropriate model. Then use those probabilities with the expected counts to conduct a Chi-squared goodness of fit test. Use a = 0.05. Frequency 12 20 23 15 13 Rate (per day) Below .100 .100 below.150 .150 - below.200 .200 - below .250 .250 or more
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