The area of the region bounded by the curves y = f(x) = 2x³ - 6x² - 2x + 6 and y = g(x) = -x³ + 3x² + x - 3 is given by: A) B) C) D) E) ¹₁ (3x³ 3x²-x+3)dx -1³(-3x³-3x²-x+3)dx [¹₁ (-3x³ +9x² + 3x −9)dx +(3x³-9x²-3x+9)dx 12³₁ (3x³-9x²-3x+9)dx (3x³-9x²-x+3)dx -(3x3-9x²-x+3)dx ¹₁ (3x³-9x²-3x+9)dx -(3x³-9x²-3x +9)dx

Q: 3. The region between the graphs of y = x3 + 4x - 1 and y = 2x3 + 3x? - 1

A:

Q: (1) Sketch the graphs y = x¹(x+2) and y = x(x+2) for the domain [-2, 1] shading the areas between…

A:

Q: 5) Sketch the graphs of the functions f and g. f(x) = x2, g(x) = 1/x2   Find the area of the region…

A: Given: fx=x2, gx=1x2 To determine: The graphs of the  given function and the area enclosed by these…

Q: Find the total areas of the shaded regions

A: Consider the given graph.The given functions are y=x2-4 and y=-x2-2x Find the intersection point of…

Q: (4) Find the area of the region bounded by f(x) = 12 - 3x², the x- - and the lines x = 0, and x = =…

A: The region bounded by functions  , the x axis and the lines  and

Q: Find the area of the region bounded by the graphs of ƒ1x2= 5 - x2 and g1x2= x2 - 3 (as shown).

A: Given fx=5-x2  and gx=x2-3 We have to find the area of bounded region.

Q: 2. f(x) = -2x2 -8x-3 -2 Vertex: AOS: Min / Max: y-int.: Domain: Range:

A: