The problem states: "The area of a rectangle is calculated as \(4x^2 - 16y^2\) square units. Which of the choices below could be the dimensions of the rectangle?"Options:A) \((2x + 4y)\) and \((2x - 4y)\)B) \((x + y)\) and \((2x - 2y)\)C) \((2x - 4y)\) and \((2x - 2y)\)D) \((x + y)\) and \((2x - 4y)\)### Explanation:The expression for the area of the rectangle, \(4x^2 - 16y^2\), resembles a difference of squares. This can be factored as follows:\[4x^2 - 16y^2 = (2x)^2 - (4y)^2 = (2x + 4y)(2x - 4y)\]Thus, the dimensions that could correspond to the rectangle are \((2x + 4y)\) and \((2x - 4y)\), which matches option A.

The area of a rectangle is calculated as 4x2 - 16y2 square units. Which of the choices below could be the dimensions of the rectangle? O (2x+4y) and (2x - 4y) O (x+y) and (2x-2y) O (2x-4y) and (2x-2y) O (x+y) and (2x - 4y)

The area of a rectangle is calculated as 4x2 - 16y2 square units. Which of the choices below could be the dimensions of the rectangle? O (2x+4y) and (2x - 4y) O (x+y) and (2x-2y) O (2x-4y) and (2x-2y) O (x+y) and (2x - 4y)

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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