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The area, A, of an isosceles right triangle varies directly as the square of the length of its leg, /. By what factor does the area increase when the length of the leg is increased by a factor of 6? A factor of 36 O A factor of 12 O A factor of 12k O A factor of 36k

The area, A, of an isosceles right triangle varies directly as the square of the length of its leg, /. By what factor does the area increase when the length of the leg is increased by a factor of 6? A factor of 36 O A factor of 12 O A factor of 12k O A factor of 36k

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The area, A, of an isosceles right triangle varies directly as the square of the length of its leg, /. By what factor does the area increase when the length of the leg is increased by a factor of 6? A factor of 36 O A factor of 12 O A factor of 12k O A factor of 36k
Transcribed Image Text:The area, A, of an isosceles right triangle varies directly as the square of the length of its leg, /. By what factor does the area increase when the length of the leg is increased by a factor of 6? A factor of 36 O A factor of 12 O A factor of 12k O A factor of 36k
The force, F, exerted by the wind on a plane surface varies jointly with the square of the velocity, v, of the wind and with the area, A, of the plane surface. If the area of the surface is 27 square feet and the wind velocity is 12 miles per hour, the resulting force is 18 pounds. Find the force on a surface of 32 square feet with a velocity of 15 miles per hour. Round the answer to the nearest tenth of a pound. O 26.7 pounds O 31.6 pounds O 33.3 pounds O 28.1 pounds
Transcribed Image Text:The force, F, exerted by the wind on a plane surface varies jointly with the square of the velocity, v, of the wind and with the area, A, of the plane surface. If the area of the surface is 27 square feet and the wind velocity is 12 miles per hour, the resulting force is 18 pounds. Find the force on a surface of 32 square feet with a velocity of 15 miles per hour. Round the answer to the nearest tenth of a pound. O 26.7 pounds O 31.6 pounds O 33.3 pounds O 28.1 pounds
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