The arclength of y = 4x² - 2 from x=0 to x = 2 is given by: -S₁²₁ OL= L= =√₁² ✓ OL= OL = 1₁₁ v L L-1₁² √² L= √1+8x²dx L= √1+64xdx Using the substitution u = 8x to re-write the integral in terms of u yields: L = '1' / | 8 L= √1+8xdx = √1+64x²dx 8 V1+ u²du √1 +4u²du 1/² √ 8 √1+ udu √1+8udu The value of this integral is: (You may need to use a table or technology to evaluate this integral.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The arclength of y = 4x² - 2 from x=0 to = 2 is given by:
-f²v
OL=
L=
OL=
=√₁² ✓
OL
L=
COL
L=₁² √₁
√1+64xdx
L=
Using the substitution u = 8x to re-write the integral in terms of u yields:
1
L = ' / |
8
=
√1+8xdx
f₁² v
√1+64x²dx
8
√1+8x²dx
√1+ u²du
√1+4u² du
1/² √
8
√1+ udu
√1+8udu
The value of this integral is:
(You may need to use a table or technology to evaluate this integral.)
Transcribed Image Text:The arclength of y = 4x² - 2 from x=0 to = 2 is given by: -f²v OL= L= OL= =√₁² ✓ OL L= COL L=₁² √₁ √1+64xdx L= Using the substitution u = 8x to re-write the integral in terms of u yields: 1 L = ' / | 8 = √1+8xdx f₁² v √1+64x²dx 8 √1+8x²dx √1+ u²du √1+4u² du 1/² √ 8 √1+ udu √1+8udu The value of this integral is: (You may need to use a table or technology to evaluate this integral.)
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