The arc length of one petal of the rose r = sin 30 is given by 1 73 2 S 2/³ TT 1 ·풍 2 S sin2 0+9 cos² 0 de 6 2 [² sin2 30+8 cos² 30 de 1+8 cos² 30 de sin² 0+9 cos² 0 de

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A: Given that  α=arcsin-23⇒sinα=-23secβ=54⇒1cosβ=54⇒cosβ=45,tanβ&lt;0

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Q: there is a mistake in the 2nd pat of the QUESTION ..but I correct it for you its "sin2x".

A: 5 (i)sin⁡z=sin⁡(x+iy)=ei(x+iy)−e−i(x+iy)2i=e−y(cos⁡x+isin⁡x)−ey(cos⁡x−isin⁡x)2i…

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A:

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Q: sec?@tan?@ + sec?@

A: We can simplify the statement as below