The aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen andlower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is 5.9 cm. If blood flows throughthe aortic arch at a speed of 0.29 m/s, what is the magnitude (in m/s²) of the blood's centripetal acceleration?Number iUnitsD¥Blood fromheartBlood toabdomen

Answered: The aorta is a major artery, rising…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

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Question

The aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen and
lower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is 5.9 cm. If blood flows through
the aortic arch at a speed of 0.29 m/s, what is the magnitude (in m/s²) of the blood's centripetal acceleration?
Number i
Units
D
¥
Blood from
heart
Blood to
abdomen

Expert Solution

Step 1

To calculate the centripetal acceleration of blood.

Given:
The diameter of the curve: $d = 5.9 cm = 5.9 \times 10^{- 2} m$
Speed of the blood flow: $v = 0.29 m/s$

To calculate:
The centripetal acceleration: $a_{c}$

The centripetal acceleration of an object moving in a circular path is calculated by the formula:
$a_{c} = \frac{v^{2}}{r}$
where,
$v$ is the linear speed of the body and
$r$ is the radius of the circular path.

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