The volume V of an ice cream cone is given by V=R³ + R²h where R is the common radius of the spherical cap and the cone, and h is the height of the cone. The volume of the ice cream cone is increasing at the rate of 10 units3/sec and its radius sincreasing at the rate of units/sec when the radius R and height h are (R, h) = (2, 3). At what rate is the heighth of the cone changing when (R, h) = (2²/₁ 14 units/sec

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The volume V of an ice cream cone is given by
-R³+R²h
플래
V =
where R is the common radius of the spherical cap and the cone, and h is the height of the cone.
h
R
The volume of the ice cream cone is increasing at the rate of 10 units/sec and its radius is increasing at the rate of units/sec when the radius R and height h are (R, h) = |
14
1
= (², ³).
units/sec
At what rate is the height ʼn of the cone changing when (R, h) = (2, 3)?
Transcribed Image Text:The volume V of an ice cream cone is given by -R³+R²h 플래 V = where R is the common radius of the spherical cap and the cone, and h is the height of the cone. h R The volume of the ice cream cone is increasing at the rate of 10 units/sec and its radius is increasing at the rate of units/sec when the radius R and height h are (R, h) = | 14 1 = (², ³). units/sec At what rate is the height ʼn of the cone changing when (R, h) = (2, 3)?
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the answer is incorrect and does not even make sense because if you have pi in the numberator and the denominator wouldnt they cancel out.

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