-4y"" + 5y" - 5y' − 3y = 0 with y(0) = -3, y'(0) = 3, y"(0) = 2. Taking the Laplace transform and solving for L(y) yields: -8s² + 3s +12 -45³+ 5s²-5s-3 Consider the differential equation L(y) F(s) where F(s) = Note: don't forget to substitute your initial conditions.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question

tried it and missed it

Consider the differential equation -4y"" + 5y" — 5y' − 3y = 0 with y(0) = −3, y'(0) = 3, y″(0) :
L(y) = F(s) where F(s) =
-8s + 3s + 12
3
2
48° +5s
5s - 3
Note: don't forget to substitute your initial conditions.
= 2. Taking the Laplace transform and solving for L(y) yields:
Transcribed Image Text:Consider the differential equation -4y"" + 5y" — 5y' − 3y = 0 with y(0) = −3, y'(0) = 3, y″(0) : L(y) = F(s) where F(s) = -8s + 3s + 12 3 2 48° +5s 5s - 3 Note: don't forget to substitute your initial conditions. = 2. Taking the Laplace transform and solving for L(y) yields:
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

Please check this

Consider the differential equation −4y" + 5y" — 5y' – 3y = 0 with y(0) = −3, y'(0) = 3, y″(0) = 2. Taking the Laplace transform and solving for L(y) yields:
12s² - 27s+22
-4s³ +5s²-5s-3
L(y) = F(s) where F(s) =
=
Note: don't forget to substitute your initial conditions.
Transcribed Image Text:Consider the differential equation −4y" + 5y" — 5y' – 3y = 0 with y(0) = −3, y'(0) = 3, y″(0) = 2. Taking the Laplace transform and solving for L(y) yields: 12s² - 27s+22 -4s³ +5s²-5s-3 L(y) = F(s) where F(s) = = Note: don't forget to substitute your initial conditions.
Solution
Bartleby Expert
SEE SOLUTION
Follow-up Question
The answer above is NOT correct.
L(y) = F(s) where F(s)
-
Entered
[12* (s^2)-27*s+7]/[-4*(s^3)+5*(s^2)-5*s-3]
Note: don't forget to substitute your initial conditions.
Answer Preview
Consider the differential equation -4y" + 5y" — 5y' – 3y = 0 with y(0) = −3, y'(0) = 3, y'(0) = 2. Taking the Laplace transform and solving for L(y) yields:
12s²_ - 27s + 7
-45³ +5s²-5s-3
128² - 27s + 7
-4s³ + 5s² - 5s - 3
Transcribed Image Text:The answer above is NOT correct. L(y) = F(s) where F(s) - Entered [12* (s^2)-27*s+7]/[-4*(s^3)+5*(s^2)-5*s-3] Note: don't forget to substitute your initial conditions. Answer Preview Consider the differential equation -4y" + 5y" — 5y' – 3y = 0 with y(0) = −3, y'(0) = 3, y'(0) = 2. Taking the Laplace transform and solving for L(y) yields: 12s²_ - 27s + 7 -45³ +5s²-5s-3 128² - 27s + 7 -4s³ + 5s² - 5s - 3
Solution
Bartleby Expert
SEE SOLUTION
Similar questions
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning