The angular speed of a rotating platform changes from ω0 = 3.8 rad/s to ω = 7.2 rad/s at a constant rate as the platform moves through an angle Δθ = 5.5 radians. The platform has a radius of R = 36 cm. a) calculate the angular acceleration of the platform in rad/s^2 b)calculate the tangential acceleration a in m's^2 of a point on the surface of the platform at the outer edge. c) calculate final centripital acceleration a in m/s^2 at the outer edge of the platform.

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Chapter1: Units, Trigonometry. And Vectors
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The angular speed of a rotating platform changes from ω0 = 3.8 rad/s to ω = 7.2 rad/s at a constant rate as the platform moves through an angle Δθ = 5.5 radians. The platform has a radius of R = 36 cm.

a) calculate the angular acceleration of the platform in rad/s^2

b)calculate the tangential acceleration a in m's^2 of a point on the surface of the platform at the outer edge.

c) calculate final centripital acceleration a in m/s^2 at the outer edge of the platform.

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     Answer:-       Given initial angular velocity ω0=3.8 rad/sec        Final angular velocity ω=7.2 rad/sec        angular displacement θ=5.5 rad.                  radius R=36 cm                            R=0.36 m    a WKT               ω2-ω02=2θ α               7.22-3.82=2×5.5×α               α=37.411          α- angular acceleration                α =3,4 rad/sec2   

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