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The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivot point L. S= Le F, cose Fsine- (a) (b)

The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivot point L. S= Le F, cose Fsine- (a) (b)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Your answer is partially correct. The angle (with respect to the vertical) of a simple pendulum is given by e = 0,mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which 0 changes with the w of the SHM.) %3D Pivot point e\L S= Le F.cose Fgsine- (a) (b) (a) Number 50.86 Unit degrees (b) Number i 0.0554 Unit rad >
Transcribed Image Text:Your answer is partially correct. The angle (with respect to the vertical) of a simple pendulum is given by e = 0,mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which 0 changes with the w of the SHM.) %3D Pivot point e\L S= Le F.cose Fgsine- (a) (b) (a) Number 50.86 Unit degrees (b) Number i 0.0554 Unit rad >
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