The analyst wanted to measure the zinc oxide content of a 1.25-g sample. The sample was treated with 50 mL of 0.5615 M sulfuric acid. Then, the resulting mixture was also treated with 0.9765 M sodium hydroxide. The resulting purity was 95.0% ZnO. A. Whatis the chemical formula zinc oxide? ZnO Zn2O ZnO2 Zn2O3 B. Whatis the chemical formula of zinc hydroxide?
For numbers A to L, consider the given case: The analyst wanted to measure the zinc oxide content of a 1.25-g sample. The sample was treated with 50 mL of 0.5615 M sulfuric acid. Then, the resulting mixture was also treated with 0.9765 M sodium hydroxide. The resulting purity was 95.0% ZnO.
A. Whatis the chemical formula zinc oxide?
-
- ZnO
- Zn2O
- ZnO2
- Zn2O3
B. Whatis the chemical formula of zinc hydroxide?
-
- ZnOH
- Zn(OH)2
- Zn(OH)3
- Zn2(OH)3
C. Whichof the following substances is the titrant?
-
- Sulfuricacid
- Sodiumhydroxide
- BothA and B
- Zincoxide
D. Whichof the following substances is the analyte?
-
- Zincoxide
- Sodiumhydroxide
- Sulfuricacid
- Bor C
E. Whatis the factor of the analyte?
-
- 1
- 2
- 3
- 4
F. Whatis the mEq of the analyte?
- 0.04900
- 0.04069
- 0.02000
- 0.02900
G. Whatis the normality of the acid?
- 0.2808 N
- 0.5616N
- 1.123N
- 2.2464N
H. Whatis the normality of the basic titrant?
- 0.4883 N
- 0.9765N
- 1.953N
- 3,906N
I. What is the %purity of magnesium oxide in thesample?
- 27.48ml
- 17.67 ml
- 43.44ml
- 19.78ml
J. Whatis the actual amount of zinc oxide in the sample?
- 0.2969g
- 0.5938g
- 1.1875g
- 2.375g
K. Thegiven case does not have a sharp end point to perform a direct
-
- True
- False
L. Theapplicable chemical indicator for this case is methyl orange.
-
- True
- False
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