The amplitude of a system moving in simple harmonic motion is doubled. Determine the change in (a) the total energy, (b) the maximum speed, (c) the maximum acceleration, and (d) the period.
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- A block is attached to a spring with a sping constant of 7.6 N/m and it undergoes simple harmonic motion. The amplitude of the blocks motion is 6.30 cm. When the block is halfway between its equilibrium position and the end point of it's motion, its speed is measured to be 28.9 cm/s. Calculate : (a) the mass of the block, (b) the period of the motion, and (c) the maximum acceleration of the block.A spring hangs vertically from a ceiling. The spring constant of the spring is k=15 N/m. A 2kg object has been attached to the spring and the spring has already come to its new equilibrium. Someone pulls the object down by 5cm and releases it at time t = 0s. The spring and object begin to oscillate under simple harmonic motion. Find the total energy of the system, the maximum kinetic energy, the maximum potential energy, and the positions where the maximum energies occur. Answers: 0.01875 J, 0.01875 JA simple pendulum with a length of 1.73 m and a mass of 6.74 kg is given an initial speed of 2.36 m/s at its equilibrium position. (a) Assuming it undergoes simple harmonic motion, determine its period (in s). (b) Determine its total energy (in J). (c) Determine its maximum angular displacement (in degrees). (For large v, and/or small /, the small angle approximation may not be good enough here.) (d) What If? Based on your answer to part (c), by what factor would the total energy of the pendulum have to be reduced for its motion to be described as simple harmonic motion using the small angle approximation where 0 ≤ 10°?
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