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The amountsS of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.936 g and a standard deviation of 0.294 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.846 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 47 cigarettes with a mean of 0.846 g or less. P(M < 0.846 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, is it valid to claim that the amoutn of nicotine is lower? O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.

The amountsS of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.936 g and a standard deviation of 0.294 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.846 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 47 cigarettes with a mean of 0.846 g or less. P(M < 0.846 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, is it valid to claim that the amoutn of nicotine is lower? O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.936 g and a standard deviation of 0.294 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.846 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 47 cigarettes with a mean of 0.846 g or less. P(M < 0.846 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, is it valid to claim that the amoutn of nicotine is lower? O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.
Transcribed Image Text:The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.936 g and a standard deviation of 0.294 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.846 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 47 cigarettes with a mean of 0.846 g or less. P(M < 0.846 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, is it valid to claim that the amoutn of nicotine is lower? O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.
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