The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.944 g and a standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.881 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 47 cigarettes with a mean of 0.881 g or less. P(M < 0.881 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut- off for our definition of unusual.) O No. The probability of obtaining this data is high enough to have been a chance occurrence. Yes. The probability of this data is unlikely to have occurred by chance alone.
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.944 g and a standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a mean nicotine amount of 0.881 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 47 cigarettes with a mean of 0.881 g or less. P(M < 0.881 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut- off for our definition of unusual.) O No. The probability of obtaining this data is high enough to have been a chance occurrence. Yes. The probability of this data is unlikely to have occurred by chance alone.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.944 g
and a standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now
reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a
mean nicotine amount of 0.881 g.
Assuming that the given mean and standard deviation have NOT changed, find the probability of
randomly selecting 47 cigarettes with a mean of 0.881 g or less.
P(M < 0.881 g) =
%3D
Enter your answer as a number accurate to 4 decimal places.
NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut-
off for our definition of unusual.)
No. The probability of obtaining this data is high enough to have been a chance occurrence.
O Yes. The probability of this data is unlikely to have occurred by chance alone.
Submit Question](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e224654-cca9-4a8b-96b7-9b4981bee880%2F96e9ddf6-263e-4ee2-835d-c591d3f77f23%2Ffureqgi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.944 g
and a standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now
reduced the amount of nicotine. The supporting evidence consists of a sample of 47 cigarettes with a
mean nicotine amount of 0.881 g.
Assuming that the given mean and standard deviation have NOT changed, find the probability of
randomly selecting 47 cigarettes with a mean of 0.881 g or less.
P(M < 0.881 g) =
%3D
Enter your answer as a number accurate to 4 decimal places.
NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut-
off for our definition of unusual.)
No. The probability of obtaining this data is high enough to have been a chance occurrence.
O Yes. The probability of this data is unlikely to have occurred by chance alone.
Submit Question
![You measure 25 randomly selected textbooks' weights, and find they have a mean weight of 38 ounces.
Assume the population standard deviation is 13.3 ounces. Based on this, construct a 90% confidence
interval for the true population mean textbook weight.
Give your answers as decimals, to two places
Submit Question](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e224654-cca9-4a8b-96b7-9b4981bee880%2F96e9ddf6-263e-4ee2-835d-c591d3f77f23%2Frm410f3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You measure 25 randomly selected textbooks' weights, and find they have a mean weight of 38 ounces.
Assume the population standard deviation is 13.3 ounces. Based on this, construct a 90% confidence
interval for the true population mean textbook weight.
Give your answers as decimals, to two places
Submit Question
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