The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.888 g and a standard deviation of 0.297 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 32 cigarettes with a mean nicotine amount of 0.804 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 32 cigarettes with a mean of 0.804 g or less. P(M < 0.804 g) =

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**Title: Analyzing Nicotine Levels in Cigarettes: A Statistical Approach**

**Introduction:**

This case study examines the nicotine content in a specific brand of cigarette. Historically, the nicotine amounts are normally distributed with a mean of 0.888 grams and a standard deviation of 0.297 grams. Recently, the company claims to have reduced the nicotine levels. A random sample of 32 cigarettes shows a mean nicotine amount of 0.804 grams. The goal is to determine the probability that this sample reflects a true reduction in nicotine levels.

**Problem Statement:**

Given that the historical mean and standard deviation have not changed, calculate the probability of randomly selecting 32 cigarettes with a mean nicotine content of 0.804 grams or less.

\[ P(M < 0.804 \, \text{g}) = \]

**Instructions:**

- Enter your calculated probability as a number accurate to four decimal places.
- You may use exact z-scores or z-scores rounded to three decimal places.

**Conclusion:**

Based on your result, decide whether the claim that the nicotine amount is lower is valid:

- **Yes.** The probability of this data is unlikely to have occurred by chance alone.
- **No.** The probability of obtaining this data is high enough to have been a chance occurrence.

**Guidance:**

For additional help or questions, please reach out to the instructor using the "Message instructor" option.

**Action:**

Click "Submit Question" after entering your response.
Transcribed Image Text:**Title: Analyzing Nicotine Levels in Cigarettes: A Statistical Approach** **Introduction:** This case study examines the nicotine content in a specific brand of cigarette. Historically, the nicotine amounts are normally distributed with a mean of 0.888 grams and a standard deviation of 0.297 grams. Recently, the company claims to have reduced the nicotine levels. A random sample of 32 cigarettes shows a mean nicotine amount of 0.804 grams. The goal is to determine the probability that this sample reflects a true reduction in nicotine levels. **Problem Statement:** Given that the historical mean and standard deviation have not changed, calculate the probability of randomly selecting 32 cigarettes with a mean nicotine content of 0.804 grams or less. \[ P(M < 0.804 \, \text{g}) = \] **Instructions:** - Enter your calculated probability as a number accurate to four decimal places. - You may use exact z-scores or z-scores rounded to three decimal places. **Conclusion:** Based on your result, decide whether the claim that the nicotine amount is lower is valid: - **Yes.** The probability of this data is unlikely to have occurred by chance alone. - **No.** The probability of obtaining this data is high enough to have been a chance occurrence. **Guidance:** For additional help or questions, please reach out to the instructor using the "Message instructor" option. **Action:** Click "Submit Question" after entering your response.
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